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yan [13]
3 years ago
5

Which of the following statements apply to electric charges?

Physics
1 answer:
Gre4nikov [31]3 years ago
6 0

Answer:

The statement "If a positively charged rod is brought close to a positively charged object, the two objects will repel " applies to electric charges.

Explanation:

There are only two types of electric charges. Both having own magnitude but different charge.

1. Positive charge

2. Negative charge

Like charges repel each other and opposite charges always attract each other.

When a positively charged rod is brought close to a positively charged object, the rod and the object will repel.

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Answer:

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Explanation:

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3 years ago
A Ford Mustang weighs about 3500 pounds, and can accelerate from 0-60 MPH in about 5 seconds. What force is responsible for this
Hunter-Best [27]

We will apply the concepts related to Newton's second law. At the same time we will convert everything to the system of international units.

m = 3500lb = 1587.57kg

The values of the velocities are,

\text{Initial Velocity} = V_i = 0

\text{Final Velocity} = V_f = 60mph = 26.822m/s

We know that the acceleration is equivalent to the change of the speed in a certain time therefore

a = \frac{v_f-v_i}{t}

a = \frac{26.822-0}{5}

a = 5.36m/s^2

Now applying the Newton's second law we have,

F= ma

F = (1587.57)(5.36)

F = 8516.36N

Therefore the approximate magnitude is 8516.36N

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3 years ago
What is the motion of the particles in this kind of wave?
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Read 2 more answers
A fisherman is fishing from a bridge and is using a "44.0-N test line." In other words, the line will sustain a maximum force of
avanturin [10]

Answer:

(a) W= 44N

(b)W= 31.65 N

Explanation:

Data

T=44 N : Maximum force that the rope can withstand without breaking

Newton's second law:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

(a)  We apply the formula (1) at constant speed , then, a=0

W: heaviest fish that can be pulled up vertically

∑F = 0

T-W =0  

W = T

W= 44N

(b)  We apply the formula (1) , a= 1.26 m/s²

W: heaviest fish that can be pulled up vertically

W= m*g

m= W/g

g= 9.8 m/s² : acceleration due to gravity

∑F = 0

T-W = m*a

T= W+(W/g)*a

44=W*(1+1/9.8)* (1.26 )

44= W* 1.39

W= 44/1.39

W= 31.65 N

7 0
3 years ago
ounces is In the apothecary system of measurement, equal to one apothecary pound. a) eight b) 16 c) 12 d) four
Tomtit [17]
The answer is one apothecary pound = 12 ounces
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