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yan [13]
3 years ago
5

Which of the following statements apply to electric charges?

Physics
1 answer:
Gre4nikov [31]3 years ago
6 0

Answer:

The statement "If a positively charged rod is brought close to a positively charged object, the two objects will repel " applies to electric charges.

Explanation:

There are only two types of electric charges. Both having own magnitude but different charge.

1. Positive charge

2. Negative charge

Like charges repel each other and opposite charges always attract each other.

When a positively charged rod is brought close to a positively charged object, the rod and the object will repel.

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Who was pedro infante?????
lys-0071 [83]

Answer: Pedro Infante Cruz (Spanish: [ˈpeðɾo iɱˈfante]; 18 November 1917 – 15 April 1957) was a Mexican actor and singer. Hailed as one of the greatest actors of the Golden Age of Mexican cinema, he is considered an idol in Mexico and other Latin American countries such as Venezuela, Guatemala and Peru.

Explanation:

5 0
3 years ago
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The displacement ‘s' of a point moving in a straight line is given by: s = 6t^2 + 5t – 5, ‘s' being in cm and ‘t' in s. The init
Ivan

Answer:

the initial velocity of the particle is 5 cm/s

Explanation:

Given initial displacement as, s = 6t² + 5t - 5

s is measured in "cm"

t is measured in "seconds"

Velocity is the rate of change of displacement with time. Expressed as follows;

v = \frac{ds}{dt} = 12t + 5

for initial velocity, time (t) = 0

v = 12(0) + 5

v = 5 cm/s

Therefore, the initial velocity of the particle is 5 cm/s

6 0
3 years ago
The ____ value of the overflow style keeps the element at the specified height and width, but cuts off excess content.
marta [7]
The appropriate response is hidden values in accordance with the overflow property. Hidden values can be as resources, for example, licenses, trademarks, or underestimated land. Financial specialists who are esteem arranged will frequently attempt to recognize an organization's hidden values.
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3 years ago
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A power lifter performs a dead lift, raising a barbell with a mass of 305 kg to a height of 0.42 m above the ground, giving the
Ann [662]

Answer:

Explanation:

Before it hits the ground:

The initial potential energy = the final potential energy + the kinetic energy

mgH = mgh + 1/2 mv²

gH = gh + 1/2 v²

v = √(2g (H - h))

v = √(2 * 9.81 m/s² * (0.42 m - 0.21 m))

v ≈ 2.0 m/s

When it hits the ground:

Initial potential energy = final kinetic energy

mgH = 1/2 mv²

v = √(2gH)

v = √(2 * 9.81 m/s² * 0.42 m)

v ≈ 2.9 m/s

Using a kinematic equation to check our answer:

v² = v₀² + 2a(x - x₀)

v² = (0 m/s)² + 2(9.8 m/s²)(0.42 m)

v ≈ 2.9 m/s

3 0
3 years ago
Can someone help me a bit on this? Will mark brainliest. ( no physical science option soooo)
Advocard [28]

Answer:

When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.

The corresponding relation for diffraction is

d sin(\theta) \approx \lambda,

where \lambda is the wavelength of light, d is the slit width, and \theta is the diffraction angle.

From this relation we clearly see that the diffraction angle \theta is directly proportional to the wavelength  \lambda of light—longer the wavelength larger the diffraction angle.

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3 years ago
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