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klio [65]
3 years ago
8

G)(Sin 5A - Sin 7A - Sin 4A + Sin 8A)÷(Cos 4A - Cos 5A - Cos 8A + Cos 7A)=Cot 6A​

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

We use a similar strategy as in your previous question. Rewrite:

sin(5<em>x</em>) = sin(6<em>x</em> - <em>x</em>) = sin(6<em>x</em>) cos(<em>x</em>) - cos(6<em>x</em>) sin(<em>x</em>)

sin(7<em>x</em>) = sin(6<em>x</em> + <em>x</em>) = sin(6<em>x</em>) cos(<em>x</em>) + cos(6<em>x</em>) sin(<em>x</em>)

→ sin(5<em>x</em>) - sin(7<em>x</em>) = -2 cos(6<em>x</em>) sin(<em>x</em>)

sin(4<em>x</em>) = sin(6<em>x</em> - 2<em>x</em>) = sin(6<em>x</em>) cos(2<em>x</em>) - cos(6<em>x</em>) sin(2<em>x</em>)

sin(8<em>x</em>) = sin(6<em>x</em> + 2<em>x</em>) = sin(6<em>x</em>) cos(2<em>x</em>) + cos(6<em>x</em>) sin(2<em>x</em>)

→   sin(8<em>x</em>) - sin(4<em>x</em>) = 2 cos(6<em>x</em>) sin(2<em>x</em>)

cos(5<em>x</em>) = cos(6<em>x</em> - <em>x</em>) = cos(6<em>x</em>) cos(<em>x</em>) + sin(6<em>x</em>) sin(<em>x</em>)

cos(7<em>x</em>) = cos(6<em>x</em> + <em>x</em>) = cos(6<em>x</em>) cos(<em>x</em>) - sin(6<em>x</em>) sin(<em>x</em>)

→   cos(7<em>x</em>) - cos(5<em>x</em>) = -2 sin(6<em>x</em>) sin(<em>x</em>)

cos(4<em>x</em>) = cos(6<em>x</em> - 2<em>x</em>) = cos(6<em>x</em>) cos(2<em>x</em>) + sin(6<em>x</em>) sin(2<em>x</em>)

cos(8<em>x</em>) = cos(6<em>x</em> + 2<em>x</em>) = cos(6<em>x</em>) cos(2<em>x</em>) - sin(6<em>x</em>) sin(2<em>x</em>)

→   cos(4<em>x</em>) - cos(8<em>x</em>) = 2 sin(6<em>x</em>) sin(2<em>x</em>)

Then

(sin(5<em>x</em>) - sin(7<em>x</em>) - sin(4<em>x</em>) + sin(8<em>x</em>)) / (cos(4<em>x</em>) - cos(5<em>x</em>) - cos(8<em>x</em>) + cos(7<em>x</em>))

= (2 cos(6<em>x</em>) sin(2<em>x</em>) - 2 cos(6<em>x</em>) sin(<em>x</em>)) / (2 sin(6<em>x</em>) sin(2<em>x</em>) - 2 sin(6<em>x</em>) sin(<em>x</em>))

= (2 cos(6<em>x</em>) (sin(2<em>x</em>) - sin(<em>x</em>))) / (2 sin(6<em>x</em>) (sin(2<em>x</em>) - sin(<em>x</em>)))

= cos(6<em>x</em>) / sin(6<em>x</em>)

= cot(6<em>x</em>)

QED

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