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klio [65]
3 years ago
8

G)(Sin 5A - Sin 7A - Sin 4A + Sin 8A)÷(Cos 4A - Cos 5A - Cos 8A + Cos 7A)=Cot 6A​

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

We use a similar strategy as in your previous question. Rewrite:

sin(5<em>x</em>) = sin(6<em>x</em> - <em>x</em>) = sin(6<em>x</em>) cos(<em>x</em>) - cos(6<em>x</em>) sin(<em>x</em>)

sin(7<em>x</em>) = sin(6<em>x</em> + <em>x</em>) = sin(6<em>x</em>) cos(<em>x</em>) + cos(6<em>x</em>) sin(<em>x</em>)

→ sin(5<em>x</em>) - sin(7<em>x</em>) = -2 cos(6<em>x</em>) sin(<em>x</em>)

sin(4<em>x</em>) = sin(6<em>x</em> - 2<em>x</em>) = sin(6<em>x</em>) cos(2<em>x</em>) - cos(6<em>x</em>) sin(2<em>x</em>)

sin(8<em>x</em>) = sin(6<em>x</em> + 2<em>x</em>) = sin(6<em>x</em>) cos(2<em>x</em>) + cos(6<em>x</em>) sin(2<em>x</em>)

→   sin(8<em>x</em>) - sin(4<em>x</em>) = 2 cos(6<em>x</em>) sin(2<em>x</em>)

cos(5<em>x</em>) = cos(6<em>x</em> - <em>x</em>) = cos(6<em>x</em>) cos(<em>x</em>) + sin(6<em>x</em>) sin(<em>x</em>)

cos(7<em>x</em>) = cos(6<em>x</em> + <em>x</em>) = cos(6<em>x</em>) cos(<em>x</em>) - sin(6<em>x</em>) sin(<em>x</em>)

→   cos(7<em>x</em>) - cos(5<em>x</em>) = -2 sin(6<em>x</em>) sin(<em>x</em>)

cos(4<em>x</em>) = cos(6<em>x</em> - 2<em>x</em>) = cos(6<em>x</em>) cos(2<em>x</em>) + sin(6<em>x</em>) sin(2<em>x</em>)

cos(8<em>x</em>) = cos(6<em>x</em> + 2<em>x</em>) = cos(6<em>x</em>) cos(2<em>x</em>) - sin(6<em>x</em>) sin(2<em>x</em>)

→   cos(4<em>x</em>) - cos(8<em>x</em>) = 2 sin(6<em>x</em>) sin(2<em>x</em>)

Then

(sin(5<em>x</em>) - sin(7<em>x</em>) - sin(4<em>x</em>) + sin(8<em>x</em>)) / (cos(4<em>x</em>) - cos(5<em>x</em>) - cos(8<em>x</em>) + cos(7<em>x</em>))

= (2 cos(6<em>x</em>) sin(2<em>x</em>) - 2 cos(6<em>x</em>) sin(<em>x</em>)) / (2 sin(6<em>x</em>) sin(2<em>x</em>) - 2 sin(6<em>x</em>) sin(<em>x</em>))

= (2 cos(6<em>x</em>) (sin(2<em>x</em>) - sin(<em>x</em>))) / (2 sin(6<em>x</em>) (sin(2<em>x</em>) - sin(<em>x</em>)))

= cos(6<em>x</em>) / sin(6<em>x</em>)

= cot(6<em>x</em>)

QED

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<em>The graph is shown in the attached picture.</em>

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Step-by-step explanation:

1) This question may be easily answered if you are aware of the shape of the graph of sq. root x, and the effect of translations to graphs.

1. x - 7 means that the original graph is translated 7 units in the positive direction of the x-axis (ie. to the right), thus the minimum value for x is also shifted from 0 to 7

2. the + 9 means that the graph is translated 9 units in the positive direction of the y-axis (ie. up), thus the minimum y-value is also shifted from 0 to 9

3. We know that the graph will continue to infinity, both in the x- and y-direction

Thus, the domain would be [7, ∞) and the range [9, ∞)

2) Another way to think about it is to ask yourself when it would make sense for the graph to exist. For this, we must consider that you cannot take the square root of a negative number.

Thus, if we have the square root of (x - 7), for what value of x would (x - 7) be negative? If x = 7:

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Therefor, any x-value less than 7 will lead to a negative answer, which wouldn't be practical. Any value equal to or greater than 7 will lead to a positive answer, thus the permissible values for x are from 7 to infinity, and so the domain is [7, ∞) (note that square brackets are used for 7 as it is included in the domain, whereas infinity is always closed with round brackets).

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