1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gekata [30.6K]
3 years ago
8

A recent study reported that high school students spend an average of 94 minutes per day texting. Jenna claims that the average

for the students at her large high school is greater than 94 minutes. She will conduct a study to investigate this claim.
(b) Based on a sample of 32 students, Jenna calculated a sample mean of 96.5 minutes and a sample standard deviation of 6.3 minutes. Assume all conditions for inference are met. At the significance level of α=0.05, do the data provide convincing statistical evidence to support Jenna’s claim? Complete an appropriate inference procedure to support your answer.
Mathematics
1 answer:
larisa [96]3 years ago
3 0

Answer:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

Step-by-step explanation:

Jenna claims that the average time of texting at her larger high school is greater than 94 minutes per day.

From here we can see that we have to perform a hypothesis test about a sample mean. The null and alternate hypothesis will be:

Null Hypothesis: \mu \leq  94

Alternate Hypothesis: \mu > 94

Jenna collected data from a sample of 32 students. So, sample size will be:

Sample Size = n = 32

Sample Mean = x = 96.5

Sample Standard Deviation = s = 6.3

We have to perform a hypothesis test, to test Jenna's claim. Since, the value of Population Standard Deviation is unknown and the value of Sample Standard Deviation is known, we will use One Sample t-test in this case.

The formula to calculate the test statistic is:

t=\frac{x-\mu}{\frac{s}{\sqrt{n}}}

Using the values, we get:

t=\frac{96.5-94}{\frac{6.3}{\sqrt{32} } }=2.245

The degrees of freedom will be:

df = n - 1 = 32 - 1 = 31

We have to convert the t-score 2.245 with 31 degrees of freedom to its equivalent p-value. From t-table this value comes out to be:

p-value = 0.0160

The significance level is:

\alpha =0.05

Since, the p-value is lesser than the level of significance, we reject the Null Hypothesis.

Conclusion:

We have sufficient evidence to support the claim that the average for the students at Jenna's large high school is greater than 94 minutes.

You might be interested in
What are the real and complex solutions of the polynomial equation? x^3-64=0
Marrrta [24]

Answer:

Step-by-step explanation:

A difference of two perfect cubes,  x^3 - y^3 can be factored into

(x-y) • (x^2 +xy +y^2) =0  equation 1

x ^3 - 64 = 0

(x)^3 - (4)^3 = 0   equation 2

Now substituting equation 2 into equation 1, we get

(x-4) (x^2+(x).(4) +(4)^2) = 0

(x-4) (x^2+4x+16) = 0

so the solutions are

1) x - 4 =0

x=4

x^2 + 4x + 16 = 0

By using the quadratic formula we get the followig solutions:

          - B  ±  √ B2-4AC

 x =   ————————

                     2A

x =(-4-√-48)/2=-2-2i√ 3 = -2.0000-3.4641i

x =(-4+√-48)/2=-2+2i√ 3 = -2.0000+3.4641i

4 0
3 years ago
How to simplify 6+(4×7
Tresset [83]
First you do the multiplication ( 4 x 7) then add 6
28 + 6 = 34
8 0
2 years ago
A company services home air conditioners. It is known that times for service calls follow a normal distribution with a mean of 7
SCORPION-xisa [38]

Answer:

The probability that exactly eight of them take more than 93.6 minutes is 5.6015 \times 10^{-6} .

Step-by-step explanation:

We are given that it is known that times for service calls follow a normal distribution with a mean of 75 minutes and a standard deviation of 15 minutes.

A random sample of twelve service calls is taken.

So, firstly we will find the probability that service calls take more than 93.6 minutes.

Let X = <u><em>times for service calls.</em></u>

So, X ~ Normal(\mu=75,\sigma^{2} =15^{2})

The z-score probability distribution for the normal distribution is given by;

                              Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean time = 75 minutes

           \sigma = standard deviation = 15 minutes

Now, the probability that service calls take more than 93.6 minutes is given by = P(X > 93.6 minutes)

       P(X > 93.6 min) = P( \frac{X-\mu}{\sigma} > \frac{93.6-75}{15} ) = P(Z > 1.24) = 1 - P(Z \leq 1.24)

                                                                = 1 - 0.8925 = <u>0.1075</u>

The above probability is calculated by looking at the value of x = 1.24 in the z table which has an area of 0.8925.

Now, we will use the binomial distribution to find the probability that exactly eight of them take more than 93.6 minutes, that is;

P(Y = y) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; y = 0,1,2,3,.........

where, n = number of trials (samples) taken = 12 service calls

            r = number of success = exactly 8

            p = probability of success which in our question is probability that

                   it takes more than 93.6 minutes, i.e. p = 0.1075.

Let Y = <u><em>Number of service calls which takes more than 93.6 minutes</em></u>

So, Y ~ Binom(n = 12, p = 0.1075)

Now, the probability that exactly eight of them take more than 93.6 minutes is given by = P(Y = 8)

               P(Y = 8)  =  \binom{12}{8}\times 0.1075^{8} \times (1-0.1075)^{12-8}

                             =  495 \times 0.1075^{8} \times 0.8925^{4}

                             =  5.6015 \times 10^{-6} .

6 0
3 years ago
Do the following lengths form a right triangle? (Also how to tell that they do form a right triangle)
ololo11 [35]

Answer: Yes this is a right triangle

We can determine this by using the converse of the pythagorean theorem.

a = 5, b = 12, c = 13

a^2 + b^2 = c^2\\\\5^2 + 12^2 = 13^2\\\\25 + 144 = 169\\\\169 = 169 \ \ \checkmark\\\\

Since those a,b,c values work in the pythagorean theorem, this proves we have a right triangle.

4 0
1 year ago
Solve the inequality for v. -5v&lt;10
koban [17]
For short answers like this use Photomath
6 0
3 years ago
Other questions:
  • If someone could help with this one 2 it would be greatly appreciated
    11·1 answer
  • Delila earns $108.75 for working 15 hours as a holiday helper wrapping gifts. at this rate ,how much money will she earn if she
    8·2 answers
  • The glee club needs to raise money for the spring trip to Europe, so the members are assembling holiday wreaths to sell. Before
    11·2 answers
  • Three consecutive intergers have a sum of 234. What are the three intergers
    6·2 answers
  • Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
    13·2 answers
  • How many fewer minutes does it take to drive 35 miles at 30 MPH than to drive the same distance at 25 mph
    15·1 answer
  • Susan determined that the expression below is equal to 7.59
    7·2 answers
  • 20 points i will give bairnleast <br> tips for making a good bridge in a essay
    6·2 answers
  • You go to your favorite store and buy 3 hats h and 2 scarves s you spent $36 total
    14·2 answers
  • Rachel enjoys exercising outdoors. Today she walked 5 2/3 miles in 2 2/3 hours. What is Rachel’s unit walking rate in miles per
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!