41
3 times 9 is 27
27+14=41
(x² + 4x - 45)/(x² + 10x + 9)
<span>
Numerator = N = x² + 4x - 45 </span>
= x² + 9x - 5x - 45
= (x² + 9x) - (5x + 45)
= x(x + 9) - 5(x + 9)
= (x + 9)(x - 5)
<span>
Denominator = D = x² + 10x + 9 </span>
= x² + x + 9x + 9
= (x² + x) + (9x + 9)
= x(x + 1) + 9(x + 1)
= (x + 1)(x + 9)
<span>
Hence, the given expr. = N/D </span>
= {(x + 9)(x - 5)}/{(x + 1)(x + 9)
= (x - 5)/(x + 1)
<span>
Restrictions : x ≠ - 1, x = 5 </span>
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This is the same as any math problem you may have solved before.
First, start by isolating the x on one side. I will choose to keep the coefficient positive, so I will add x to both sides.
6>2x+2
Subtract 2
4>2x
Divide by 2
2>x
Or
x<2
