2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35
OR
((n-1)x8)+3
1/(1/R1 + 1/R2 + 1/R3)
= 1/ (R2R3 + R1R3 + R1R2)/R1R2R3
= R1R2R3/ (R2R3 + R1R3 + R1R2)
Check the picture below.
the segment LOJ is a diameter, and therefore the arcLCJ made by that diameter will have a central angle of 180°.
that simply means that the arcLC is 180 - 94, or 86°.
the ∡LJC is an inscribed angle that is intercepting the arcLC, and therefore, by the inscribed angle theorem, it'll be half of arcLC.
Answer:
a = 0
Step-by-step explanation:
=> 3(a+4)-5(a-2) = 22
Opening Brackets
=> 3a+12-5a+10 = 22
=> 3a-5a+12+10 = 22
=> -2a+22 = 22
Subtracting 22 to both sides
=> -2a = 0
Dividing both sides by -2
We get,
=> a = 0
Answer:
0
Step-by-step explanation:
→ First find inverse cosine 1/2
60°
→ Now multiply this answer by 3 because then if you substitute it in you get 0.5
∝ = 180°
→ Now find sine of 180°
0