Explanation:
1. neutrons
2. protons
3. protons and neutrons
4. neutrons
5. electrons
I'm not sure with 1 and 4, sorry :<
A compound accepts electrons from another substance to form a covalent bond. The compound acts as a Lewis base.
<h3>What are the most common acid-base theories?</h3>
- Arrhenius: acids release H⁺ and bases release OH⁻.
- Bronsted-Lowry: acids donate H⁺ and bases accept H⁺.
- Lewis: acids accept electrons and bases donate electrons.
A compound accepts electrons from another substance to form a covalent bond. Which term best describes this compound’s behavior?
- Lewis acid. YES.
- Arrhenius base. NO, because OH⁻ is not involved.
- Bronsted-Lowry acid. NO, because H⁺ is not involved.
- Bronsted-Lowry base. NO, because H⁺ is not involved.
A compound accepts electrons from another substance to form a covalent bond. The compound acts as a Lewis base.
Learn more about Lewis acid-base theory here: brainly.com/question/7031920
He was involved in the mapping of venus and mars
setup 1 : to the right
setup 2 : equilibrium
setup 3 : to the left
<h3>Further explanation</h3>
The reaction quotient (Q) : determine a reaction has reached equilibrium
For reaction :
aA+bB⇔cC+dD
![\tt Q=\dfrac{C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=%5Ctt%20Q%3D%5Cdfrac%7BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
Comparing Q with K( the equilibrium constant) :
K is the product of ions in an equilibrium saturated state
Q is the product of the ion ions from the reacting substance
Q <K = solution has not occurred precipitation, the ratio of the products to reactants is less than the ratio at equilibrium. The reaction moved to the right (products)
Q = Ksp = saturated solution, exactly the precipitate will occur, the system at equilibrium
Q> K = sediment solution, the ratio of the products to reactants is greater than the ratio at equilibrium. The reaction moved to the left (reactants)
Keq = 6.16 x 10⁻³
Q for reaction N₂O₄(0) ⇒ 2NO₂(g)
![\tt Q=\dfrac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=%5Ctt%20Q%3D%5Cdfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
Setup 1 :
Q<K⇒The reaction moved to the right (products)
Setup 2 :
Q=K⇒the system at equilibrium
Setup 3 :
Q>K⇒The reaction moved to the left (reactants)
Answer:
Boron and Aluminium
Explanation:
Boron and Aluminium are present in Group 13 of the modern periodic table. Group 13 (IUPAC System) can also be referred to as Group III-A. Logically, Boron and Aluminum can't be placed alongwith elements such as Yttrium as they don't exhibit properties of a transition metal.
