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Aneli [31]
3 years ago
9

The graphic shows two isomers of a chemical compound with molecular formula C5H11NO2. Which type of isomers are these? A. struct

ural isomers B. geometric isomers C. halotropic isomers
Chemistry
2 answers:
vichka [17]3 years ago
8 0

Answer:

<u><em>structural isomers.</em></u>

Explanation:

Plato Users

-BARSIC- [3]3 years ago
6 0
The two compounds shown indeed have tha same molecular formula, C5 H11 NO2. One of the molecules has a group NH2 and a group COOH, the other molecule has a NOO group, that makes that the two isomers have a completely different structure, with the atoms arranged in a completely different order. <span>This kind of isomers fits in the definition of structural isomers, so the answer is structural isomers.</span>
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A sample of O2 gas (2.0 mmol) effused through a pinhole in 5.0 s. It will take __________ s for the same amount of CO2 to effuse
ludmilkaskok [199]

Answer:

\large \boxed{\text{5.9 s}}

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases, the ratio of their rates of effusion is

\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

The time for diffusion is inversely proportional to the rate.

\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}

Let CO₂ be Gas 1 and O₂ be Gas 2

Data:

M₁ = 44.01

M₂ = 32.00

Calculation

\begin{array}{rcl}\dfrac{t_{2}}{t_{1}} & = & \sqrt{\dfrac{M_{2}}{M_{1}}}\\\\\dfrac{t_{2}}{\text{5 s}}& = & \sqrt{\dfrac{44.01}{32.00}}\\\\& = & \sqrt{1.375}\\t_{2}& = & \text{5 s}\times 1.173\\& = & \mathbf{5.9 s} \\\end{array}\\\text{It will take $\large \boxed{\textbf{5.9 s}}$ for the carbon dioxide to effuse.}

4 0
3 years ago
How many atoms of phosphorus are in 4.5 grams of tetraphosphorus decoxide?
Alexxx [7]

Answer:

In 4.5 grams of tetraphosphorus decoxide we have 3.85 * 10^22  phosphorus atoms

Explanation:

Step 1: Data given

tetraphosphorus decoxide = P4O10

Molar mass of P4O10 = 283.89 g/mol

Mass of P4O10 = 4.5 grams

Number of Avogadro = 6.022 * 10^23 / mol

Step 2: Calculate moles of P4O10

Moles P4O10 = mass P4O10 / molar mass P4O10

Moles P4O10 = 4.5 grams / 283.89 g/mol

Moles = 0.016 moles

Step 3: Calculate moles of P

For 1 mol P4O10 we have 4 moles of phosphorus

For 0.016 moles P4O10 we have 4*0.016 = 0.064 moles P

Step 4: Calculate number of P atoms

Number of P atoms = moles P * number of Avogadro

Number of P atoms = 0.064 moles * 6.022*10^23

Number of P atoms = 3.85 * 10^22 atoms

In 4.5 grams of tetraphosphorus decoxide we have 3.85 * 10^22  phosphorus atoms

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3 years ago
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