Answer:
Distance, direction and symbol.
Explanation:
Distance, direction and symbol are the three components of the map which make a complete description of a location. On the map, these three components are present which provides information about a specific location on the map. Map is a drawing on the paper that shows the geography of the whole world and provides information in detail.
Based on our knowledge of strong and weak acids, we can confirm that the Ka value for acetic acid will be relatively low since it is a weak acid.
Acids can be strong or weak. This is determined by its <u><em>tendency to break apart into ions or stay together to form molecules.</em></u> Although somewhat counter-intuitive, strong acids are those that are most likely to break apart and therefore contain a <em><u>high number of </u></em><em><u>ions </u></em><em><u>within their solutions</u></em>.
Weak acids, on the other hand, are those that<em><u> tend to stay together in the form of </u></em><em><u>molecules </u></em><em><u>and therefore possess very </u></em><em><u>low ion counts </u></em><em><u>in their solutions.</u></em> The acid dissociation constant, Kₐ, is used to measure whether an acid is weak or strong and how much so. In the case of Acetic acid, the ka measurement will offer a low value, indicating a weak acid.
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Answer:
see explanations
Explanation:
4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)
Ci(NH₃) = 3.5mole/4L = 0.875M
Cf(NH₃) = 1.6mole/4L = 0.400M
Rate-1 => Δ[NH₃]/Δt = |(0.400M - 0.875M)/3min| = 0.158M/s
Rate-2 => 6(Δ[NH₃]/Δt) = 4(Δ[H₂O]/Δt) => 6/4(0.158M/s) = 0.237M/s
Rate-3 => 5(Δ[NH₃]/Δt) = 4(Δ[O₂]/Δt) => 5/4(0.158M/s) = 0.237M/s
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NOTE: When setting up comparative rate expressions for a given reaction, set the rates expressions as equal then swap coefficient values. Then solve for rate of interest and substitute givens.
example: for NH₃ and H₂O
- set rates expressions equal => Δ[NH₃]/Δt = Δ[H₂O]/Δt
- then swap and insert coefficients from given rxn ...
- solve for rate of interest ...
4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)
=> 6(Δ[NH₃]/Δt) = 4(Δ[H₂O]/Δt)
=> Δ[H₂O]/Δt = 6/4(Δ[NH₃]/Δt) = 6/4(0.237M/s) = 0.237M/s
Without conducting an experiment, one can determine if a species in a solution is acidic or basic by using a litmus paper.
<h3>Litmus test</h3>
Acidic species would turn a blue litmus paper to red but have no effects on red litmus paper.
Basic species would turn a red litmus paper to blues but have no effects on blue litmus paper.
Thus, in order to determine if a species in a solution is acidic or basic without conducting any experiment, dipping a litmus paper into the solution would give an indication.
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A cyclone rotates faster and faster as pressure differences between areas of low and high pressure increases