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scoundrel [369]

2 years ago

9

How many grams of magnesium metal will react completely with 5.2 liters of 4.0 M HCl?

1 answer:

neonofarm [45]2 years ago

4 0

1) Find the number of mols of HCl in 5.2 liters of 4.0M solution:

n = M*V(L) = 4.0 mol/L * 5.2 L = 20.8 mol

2) Find the number of mols of Mg that will react with 20.8 mol of HCl, using the coefficients of the balanced equation

[1mol Mg / 2 mol HCl] * 20.8 mol HCl = 10.4 mol Mg

3) Transform mol to mass using the atomic mass:

10.4 mol Mg * 24.3 g/mol = 252.7 g of Mg.

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A sample of gold has a mass of 67.2 g and a volume of 3.5 cm3. the density of gold is

scoray [572]

67.2g/3.5cm3= 19.2g/cm3

6 0

3 years ago

What is the mole ratio needed to determine the mass of phosphorus trifluoride produced from the reaction of 120 g of phosphorus

Vitek1552 [10]

Answer:

$\frac{4molPF_3}{1molP_4}$

Explanation:

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In this case, given the reaction:

$P_4(s)+6F_2(g)\rightarrow 4PF_3(g)$

It means that since the coefficients preceding phosphorous and phosphorous trifluoride are 1 and 4, the correct mole ratio should be:

$\frac{4molPF_3}{1molP_4}$

Because given the mass of phosphorous it is convenient to convert it to moles and then cancel it out with the moles on bottom of the mole ratio.

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8 0

2 years ago

Help! The products of a chemical equation are CO2 and 2H20. Which set of atoms

elixir [45]

D. Ap3x just did it

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5 0

2 years ago

Read 2 more answers

tekilochka [14]

The answer is A. Has a low pH in solution.

5 0

2 years ago

pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒ $\frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}$

or,

⇒ $Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr$

⇒ $=\frac{1}{2}\times 4.96$

⇒ $=2.48 \ mole$

(b)

The limiting reactant is:

= $HBr$

(c)

The excess reactant is:

= $Al$

6 0

2 years ago