Answer : The pH of the solution is, 5.24
Explanation :
First we have to calculate the volume of 
Formula used :
where,
are the initial molarity and volume of 
.
are the final molarity and volume of .
We are given:
Putting values in above equation, we get:
Now we have to calculate the total volume of solution.
Total volume of solution = Volume of + Volume of
Total volume of solution = 160.0 mL + 1086.79 mL
Total volume of solution = 1246.79 mL
Now we have to calculate the Concentration of salt.
Now we have to calculate the pH of the solution.
At equivalence point,
![pOH=\frac{1}{2}[pK_w+pK_b+\log C]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5BpK_w%2BpK_b%2B%5Clog%20C%5D)
![pOH=\frac{1}{2}[14+4.87+\log (0.0437)]](https://tex.z-dn.net/?f=pOH%3D%5Cfrac%7B1%7D%7B2%7D%5B14%2B4.87%2B%5Clog%20%280.0437%29%5D)
Thus, the pH of the solution is, 5.24
Answer:the answer is b
Explanation:I took the test and got it right
Answer:
3.64g
Explanation:
Given parameters:
Mass of NH₃ = 18.1g
Mass of Cu₂O = 90.4g
Unknown:
Limiting reactant = ?
Mass of N₂ formed = ?
Solution:
The reaction equation is given as:
Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O
The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;
Number of moles = 
Molar mass of Cu₂O = 2(63.6) + 16 = 143.2g/mol
Molar mass of NH₃ = 14 + 3(1) = 17g/mol
Number of moles of Cu₂O = 
= 0.13moles
Number of moles of NH₃ = 
= 5.32moles
From this reaction;
1 mole of Cu₂O combines with 2 mole of NH₃
So 0.13moles of Cu₂O will combine with 0.13 x 2 mole of NH₃
= 0.26moles of NH₃
Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;
Mass of N₂;
Mass = number of moles x molar mass
1 mole of Cu₂O will produce 1 mole of N₂
0.13 mole of Cu₂O will produce 0.13 mole of N₂
Mass = 0.13 x (2 x 14) = 3.64g
Answer:
B. CH3Br
Explanation:
Dipole -Dipole interactions take place in polar molecules.
CH3Br exhibits dipole -dipole forces as its strongest attraction between molecules because it is a polar molecule due to the slightly negative dipole present on the Br molecule.
While O2 is a nonpolar molecule due to its linear structure, CCl4 has zero resultant dipole moment, Helium is non-polar and BrCH2CH2OH is a non polar compound having net dipole moment is zero.
Hence, the correct option is B. CH3Br.
