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sveticcg [70]
3 years ago
7

What is silicons reactivity level

Chemistry
2 answers:
snow_lady [41]3 years ago
8 0

Answer:

Silicon, like carbon, is relatively inactive at ordinary temperatures; but when heated it reacts vigorously with the halogens (fluorine, chlorine, bromine, and iodine) to form halides and with certain metals to form silicides.

egoroff_w [7]3 years ago
5 0

Answer:

this is your answer

Explanation:

Silicon, like carbon, is relatively inactive at ordinary temperatures; but when heated it reacts vigorously with the halogens (fluorine, chlorine, bromine, and iodine) to form halides and with certain metals to form silicides.

hope it helps

good day (≧▽≦)

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How is beryllium similar to calcium?<br>​
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Answer:

The second column on the periodic table of the chemical elements is collectively called the alkaline earth metal group: beryllium, magnesium, calcium, strontium, barium, and radium. Because the outer electron structure in all of these elements is similar, they all have somewhat similar chemical and physical properties.

Explanation:

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3 years ago
PLEASE HELP!!!!! I need help with this question!
Ivahew [28]

Answer:

Exothermic Reaction

Explanation:

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How many molecules of sodium nitrate are produced when 40 g of sodium azide, NaN3, react with oxygen?
quester [9]
NaN 3 + AgNO 3 AgN 3 + NaNO 3
3 0
2 years ago
The enthalpies of formation of the compounds in the combustion of methane, , are CH4 (g): Hf = –74.6 kJ/mol; CO2 (g): Hf = –393.
algol [13]

Answer:

The amount of energy released from the combustion of 2 moles of methae is 1,605.08 kJ/mol

Explanation:

The chemical reaction of the combustion of methane is given as follows;

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (g)

Hence, 1 mole of methane combines with 2 moles of oxygen gas to form 1 mole of carbon dioxide and 2 moles of water vapor

Where:

CH₄ (g): Hf = -74.6 kJ/mol

CO₂ (g): Hf = -393.5 kJ/mol

H₂O (g): Hf = -241.82 kJ/mol

Therefore, the combustion of 1 mole of methane releases;

-393.5 kJ/mol × 1 + 241.82 kJ/mol × 2 + 74.6 kJ/mol = -802.54 kJ/mol

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2 × -802.54 kJ/mol or 1,605.08 kJ/mol.

8 0
3 years ago
Read 2 more answers
Assuming that the solubility of radon in water with 1 atm pressure of the gas over the water at 30 ∘C is 7.27×10−3M, what is the
Daniel [21]

Answer:

K = 137.55 atm/M.

Explanation:

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<em>P = (K)(C)</em>

where P is the partial pressure of the gaseous  solute above the solution (P = 1.0 atm).

k is a constant (Henry’s constant).

C is the concentration of the dissolved gas (C = 7.27 x 10⁻³ M).

∴ K = P/C = (1.0 atm)/(7.27 x 10⁻³ M) = 137.55 atm/M.

4 0
3 years ago
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