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barxatty [35]
3 years ago
6

NEED HELP ASAP PLS

Mathematics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer: YOU NEED TO FIGURE IT OUT ASAP PLS

Step-by-step explanation:

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Someone help me answer this pls
andriy [413]

Answer:

y>-2x-3

Step-by-step explanation:

I think, not sure.

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3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet is related to the time after launch, x in seconds, by the
gizmo_the_mogwai [7]

Step-by-step explanation:

The height of the rocket y in feet is related to the time after launch, x in seconds, by the given equation i.e.

y=-16x^2+165x+78 ......(1)

It is required to find the maximum height reached by the rocket. For maximum height put \dfrac{dy}{dx}=0.

So,

\dfrac{d(-16x^2+165x+78)}{dx}=0\\\\-32x+165=0\\\\32x=165\\\\x=5.15\ s

Put x = 5.15 in equation (1).

y=-16(5.15)^2+165(5.15)+78\\\\y=503.39\ m

So, the maximum height reached by the rocket is 503.39 m.

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4 years ago
A square and a rectangle have equal areas. The length of the rectangle is twice the length of the side of the square. The width
skelet666 [1.2K]

Answer:

4 cm

Step-by-step explanation:

x^2 = bh

b = 2x

h = x-2

x^2 = (2x)(x-2)

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16 = 16

3 0
3 years ago
In triangle LMN, LM = 6, MN = 9, and LN = 7. Find m∠M to the nearest tenth of a degree.
kozerog [31]
7^2 = 6^2 + 9^2 - 2(6)(9)cos(m)
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