We are given
arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103
so, first term is 124
u(1)= 124
now, we can find common difference
now, we can find kth term
now, we can plug values
and we get
u(k) must be negative
so,
now, we can solve for k
so, it's closest integer value is
..............Answer
Answer:
21060°
Step-by-step explanation:
117x180°
=21060°
4 consecutive odd numbers....x, x + 2, x + 4, x + 6
2(x + x + 2) = 3(x + 4 + x + 6) - 40
2(2x + 2) = 3(2x + 10) - 40
4x + 4 = 6x + 30 - 40
4x + 4 = 6x - 10
4x - 6x = -10 - 4
-2x = - 14
x = -14/-2
x = 7
x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13
ur numbers are : 7,9,11,13 <==
Answer:
Step-by-step explanation:
it becomes lighter :P or maybe you could say "bouncier" :P
Answer:
x = 7 degrees
Step-by-step explanation:
4x-5 = 2x + 9
-2x -2x
2x-5 = 9
+5 +5
2x = 14
2x/2 =14 /2
x= 7
