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Helen [10]
3 years ago
11

What is the solution to the system of equations graphed below?

Mathematics
1 answer:
tatiyna3 years ago
8 0

I think it is D..

.

BMK

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Farmer x plowed 168 acres of land. This was 21% of his farm. How many acres in his farm
Bond [772]
X= total acres on farm

x * 21%= 168
move decimal 2 places to the left to go from percent to decimal form
x * 0.21= 168
divide both sides by 0.21
x= 800 acres

ANSWER: There are a total of 800 acres on the farm

Hope this helps! :)
5 0
3 years ago
Can someone help me solve for x and show the work please
Elden [556K]

Answer:

D. -10

Step-by-step explanation:

The sum of a triangle = 180°, therefore,

64° + 63° + x + 63 = 180°

Add like terms

x + 190° = 180°

Subtract 190 from each side

x + 190 - 190 = 180 - 190

x = -10

7 0
3 years ago
For binomials of the form (x - y) ^ n explain how to determine the sign of a term without writing out the entire expansion
Mnenie [13.5K]

Answer:

When raising an expression of that format to any power, after grouping like terms, you'll always find that the odd numbered terms are positive, and the even numbered terms are negative.

For example:

(x - y)² = x² − 2xy + y²

(x - y)³ = x³ − 3x²y + 3xy² − y³

(x - y)⁴ =x⁴ − 4x³y + 6x²y² − 4xy³ + y⁴

etc.

3 0
3 years ago
Which expression is equivalent to Negative 32 Superscript three-fifths?
Sidana [21]

Answer:

-8

Step-by-step explanation:

Given: (-32)^{(\frac{3}{5}) }

To choose: the correct option

Solution:

Power refers to a number of times, a number is multiplied by itself. Another name for power is exponent.

As per rule of exponents, (a^m)^n=a^{mn}

Here,

(-32)=(-2)^5

Therefore,

(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }

Here, a=-2,m=5,n=\frac{3}{5}

So,

(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }=(-2)^3=-8

8 0
3 years ago
Read 2 more answers
He temperature moreased by 8' Fahrenheit
kompoz [17]

it is B The temperature started at 78°F and increased by 6°F Then the temperature increased by 5°F

6 0
3 years ago
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