What is the solution to the system of equations graphed below?

Mathematics

1 answer:

tatiyna2 years ago

8 0

I think it is D..

BMK

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2. A 2-pint bottle of olive oil costs $2.68. If

tino4ka555 [31]

Answer:

21.44 All you need to do is divide the 2.68 by 2 then multiply it by 16

7 0

2 years ago

PLZ SOME ONE HELPS QUICK ILL GIVE 50 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!

neonofarm [45]

We already know that the distance of all the planets are generally calculated by keeping the Sun as the main location point.
Explanation:
The distances of all the planets from the Sun in scientific notation and exponential form-
Mercury-
57
million kilometers.
Scientific notation-
5.7
⋅
10
7

km

Venus-
108
million kilometers.
Scientific notation-
1.08
⋅
10
8

km

Earth-
150
million kilometers
Scientific notation-
1.5
⋅
10
8

km

Mars-
228
million kilometers
Scientific notation-
2.28
⋅
10
8

km

Jupiter-
779
million kilometers
Scientific notation-
7.79
⋅
10
8

km

Saturn-
1.43
billion kilometers
Scientific notation-
1.43
⋅
10
9

km

Uranus-
2.88
billion kilometers
Scientific notation-
2.388
⋅
10
9

km

Neptune-
4.5
billion kilometers
Scientific notation-
4.5
⋅
10
9

km

8 0

2 years ago

What is lim x→3 x^2 - x - 6/ x - 3

Kisachek [45]

<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, $\frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2$

Allowing us to say,

$\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\$