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3 years ago

Please help me with this question.

Mathematics

1 answer:

melisa1 [442]3 years ago

3 0

Answer:

you have to figure out the cordnests

Step-by-step explanation:

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Which ratio is equivalent to the ratio 2:5? a. 6:15 b. 5:2 c. 5:8 d. 4:7

Alex_Xolod [135]

The answer is A) 6:15, because if you divide both numbers by three, it'll give you 2:5

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3 years ago

Read 2 more answers

Most __________ signs are rectangular, with the longer dimension vertical, and have a white background.

Furkat [3]

Answer:

Regulatory

Step-by-step explanation:

the rectangular sign with longer vertical dimension and have white background are called regulatory signs.

regulatory signs are those signals which are used to indicate or reinforce traffic laws.

these regulatory sign informs the driver and tell them to apply the traffic law at certain required places.

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3 years ago

Please help and work please

navik [9.2K]

84-60=24
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3 years ago

HELP

TiliK225 [7]

I think it’s B I’m not sure about it but I hate wan I gat it wrong.

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2 years ago

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that $p = 0.95$

10 targets

This means that $n = 10$

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

$P(X = 10) + P(X < 10) = 1$

We want P(X < 10). So

$P(X < 10) = 1 - P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987$

$P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401$

40.1% probability that he will miss at least one of them

7 0

2 years ago

Please help me with this question.​

Please help me with this question.