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2 years ago

A single card is drawn from a standard 52 card deck.

Mathematics

1 answer:

Alecsey [184]2 years ago

3 0

Answer:

Step-by-step explanation:

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If f(x)=4x^2 and g(x)=x+1, find (fog)(x)

iren [92.7K]

Answer: The value of $(f_\circ g)(x)$ is $4(x+1)^2$ .

Step-by-step explanation:

Given: $f(x) = 4x^2 \text { and } g(x) = x+1$

To find: $(f_\circ g)(x)$

As we know it is composition function which means that g(x) function is in f(x) function.

So we have

$(f_\circ g) (x) = f[g(x)]$

$\Rightarrow( f_\circ g)(x)= f(g(x)) = 4(g(x))^2$

Now substitute the value of g(x) we get

$(f_\circ g)(x)= 4(x+1)^2$

Hence, the value of $(f_\circ g)(x)$ is $4(x+1)^2$ .

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3 years ago

Can someone help me graph the line

Scilla [17]

To find slope use the slope formula. Then, use y=mx+b. Plug in the numbers.

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3 years ago

A soccer balls outer covering is made by stitching together 12 regular pentagons and 20 regular hexagons both regular polygons h

KengaRu [80]

Http://www.madeiracityschools.org/userfiles/376/Classes/17052/Review%20Worksheet%20Unit%209%20Quiz%2...

I would use this website. Hope it helps!

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3 years ago

Write a Rule for a Composite Function

zysi [14]

Answer:

Step-by-step explanation:

Observing that <em>f</em> has to be placed inside <em>g</em>, we can easily substitute x^2 - 3 in place of the x in x + 1, making it

(x^2 - 3) + 1 which equals

(x^2) - 2

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3 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

harina [27]

$L(x,y,z,\lambda)=8x+8y+4z+\lambda(4x^2+4y^2+4z^2-36)$

$L_x=8+8\lambda x=0\implies 1+\lambda x=0$
$L_y=8+8\lambda y=0\implies 1+\lambda y=0$
$L_z=4+8\lambda z=0\implies 1+2\lambda z=0$
$L_\lambda=4x^2+4y^2+4z^2-36=0\implies x^2+y^2+z^2=9$

$yL_x=y+\lambda xy=0$
$xL_y=x+\lambda xy=0$
$\implies yL_x-xL_y=y-x=0\implies y=x$

$2zL_x=2z+2\lambda xz=0$
$xL_z=x+2\lambda xz=0$
$\implies 2zL_x-xL_z=2z-x=0\implies x=2z$

$2zL_y=2z+2\lambda yz=0$
$yL_z=y+2\lambda yz=0$
$\implies 2zL_y-yL_z=2z-y=0\implies y=2z$

$x=y=2z\implies x^2+y^2+z^2=9\iff 4z^2+4z^2+z^2=9z^2=9\implies z=\pm1$

$z=\pm1\implies y=x=\pm2$

So we have two critical points, (2, 2, 1) and (-2, -2, -1), which respectively give a max of 36 and a min of -36.

5 0

3 years ago