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Valentin [98]
3 years ago
6

Triangle PQR lies in the xy-plane, and the coordinates of vertex Q are (2, –3). Triangle PQR is rotated 180° clockwise about the

origin and then refected across the y-axis to produce triangle P′Q′R′, where vertex Q′ corresponds to vertex Q of triangle PQR. What are the coordinates of Q′?
Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

(2,3)

Step-by-step explanation:

We are given that triangle PQR lies in the xy-plane, and coordinates of Q are (2,-3).

Triangle PQR is rotated 180 degrees clockwise about the origin and then reflected across the y-axis to produce triangle P'Q'R',

We have to find the coordinates of Q'.

The coordinates of Q(2,-3).

180 degree clockwise  rotation about the origin  then transformation rule

(x,y)\rightarrow (-x,-y)

The coordinates (2,-3) change into (-2,3) after 180 degree clockwise rotation about origin.

Reflect across y- axis the transformation rule

(x,y)\rightarrow (-x,y)

Therefore, when reflect across y- axis then the coordinates (-2,3) change into (2,3).

Hence, the coordinates of Q(2,3).

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Step-by-step explanation:

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So, \frac{QD}{QR} = \frac{QC}{QS}

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The solution to given system of equations is (x, y) = (2, -1)

<em><u>Solution:</u></em>

Given system of equations are:

-1x + 2y = -4  -------- eqn 1

4x + 3y = 5 ------- eqn 2

We can solve the above system of equations by elimination method

<em><u>Multiply eqn 1 by 4</u></em>

4(-1x + 2y = -4)

-4x + 8y = -16  ------ eqn 3

<em><u>Add eqn 2 and eqn 3</u></em>

4x + 3y = 5

-4x + 8y = -16

( + ) --------------------

0x + 11y = -16 + 5

11y = -11

y = -1

<em><u>Substitute y = -1 in eqn 1</u></em>

-1x + 2(-1) = -4

-x -2 = -4

-x = -4 + 2

-x = -2

x = 2

<em><u>Check the answer:</u></em>

Substitute x = 2 and y = -1 in eqn 2

4x + 3y = 5

4(2) + 3(-1) = 5

8 - 3 = 5

5 = 5

Thus the obtained answer is correct

Thus the solution to given system of equations is (x, y) = (2, -1)

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