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Valentin [98]
3 years ago
6

Triangle PQR lies in the xy-plane, and the coordinates of vertex Q are (2, –3). Triangle PQR is rotated 180° clockwise about the

origin and then refected across the y-axis to produce triangle P′Q′R′, where vertex Q′ corresponds to vertex Q of triangle PQR. What are the coordinates of Q′?
Mathematics
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

(2,3)

Step-by-step explanation:

We are given that triangle PQR lies in the xy-plane, and coordinates of Q are (2,-3).

Triangle PQR is rotated 180 degrees clockwise about the origin and then reflected across the y-axis to produce triangle P'Q'R',

We have to find the coordinates of Q'.

The coordinates of Q(2,-3).

180 degree clockwise  rotation about the origin  then transformation rule

(x,y)\rightarrow (-x,-y)

The coordinates (2,-3) change into (-2,3) after 180 degree clockwise rotation about origin.

Reflect across y- axis the transformation rule

(x,y)\rightarrow (-x,y)

Therefore, when reflect across y- axis then the coordinates (-2,3) change into (2,3).

Hence, the coordinates of Q(2,3).

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The vertices of a rectangle are R(-5, -5), S(-1, -5), T(-1, 1), and U(-5, 1). a translation, R to the point (-4,2). Find the tra
Nikitich [7]
Translation:
R ( - 5, - 5 ) → R` ( - 4, 2 )
- 4  = - 5 + 1,   2 = - 5 + 7;
The translation rule:
( x , y ) → ( x + 1, y + 7 )
Coordinates of the point U are (- 5, 1 )
- 5 + 1 = - 4,  1 + 7 = 8
The image of U is :
U` ( - 4, 8 )
4 0
3 years ago
What two numbers add to 9 and multiply to -70
Alborosie
X, y - the numbers

The numbers add to 9 and multiply to -70.
x+y=9 \\
xy=-70 \\ \\
y=9-x \\
xy=-70 \\ \\
\hbox{substitute 9-x for y in the second equation:} \\
x(9-x)=-70 \\
9x-x^2=-70 \\
-x^2+9x+70=0 \\
-x^2+14x-5x+70=0 \\
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(-x-5)(x-14)=0 \\
-x-5=0 \ \lor \ x-14=0 \\
x=-5 \ \lor \ x=14 \\ \\
y=9-x \\
y=9-(-5) \ \lor \ y=9-14 \\
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The numbers are -5 and 14.
4 0
3 years ago
Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s
Jobisdone [24]

Answer:

f(x)=x^4-9x^2-50x-150

Step-by-step explanation:

Let f(x) be the polynomial function of minimum degree with real coefficients whose zeros are 5, -3, and -1 + 3i be f(x).

By the complex conjugate property of polynomials, -1-3i is also a root of this polynomial.

Therefore the polynomial in factored form is f(x)=(x-5)(x+3)(x-(-1+3i))(x-(-1+3i))

We expand to get:f(x)=(x^2-2x-15)(x^2+2x+10)

We expand further to get:\

f(x)=x^4-9x^2-50x-150

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3 years ago
What is the equation of this line?<br> Y= 2x - 3<br> y=-x-3y = -2x - 3<br> y = x - 3
kobusy [5.1K]

Answer: y=2x-3

Step-by-step explanation:

It will cross the y axis at -3 and the x axis at 3/2

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3 years ago
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Answer:

2,401 yards long

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9,604 divided by 4 = 2,401

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