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3 years ago

Charlie buys a cake for $23.99 and 6 bags of balloons. About how much money does he spend?

Mathematics

2 answers:

Yuri [45]3 years ago

7 0

<span>47.69 is his cost amount</span>

ruslelena [56]3 years ago

6 0

6 baloons
6 times 3.95 is 23.7
so total is cake+ballons=23.99+23.7=47.69

total is $47.69

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2 3/5 convert to decinal

Leokris [45]

So we know that 1/5=0.2

Then we take 5/5=1.0

Then we solve 2*1.0=2.0

Now we solve 1/5+1/5+1/5 or 1/5*3=0.6

So then the correct answer is 2.6

Hope this helps!!!

7 0

3 years ago

Find three consecutive odd integers such that the sum of the 1st and 2nd number is 344

olga2289 [7]

Answer:

three consecutive odd integers are.

$171, 173, 175$

Step-by-step explanation:

Let x be the first term of odd integer,

Therefore, the second consecutive odd integers = $x+2$

Similarly, the third consecutive odd integers = $x+4$

Given:

The sum of the first term and second term is 344.

first term + second term = 344

Here first term is x and second term is $x+2$ .

$x+(x+2)=344$

$2x+2=344$

$2x=344-2$

$x=\frac{342}{2}$

$x=171$

Therefore, the first odd integers is 171.

And the second consecutive odd integers = $x+2=171+2=173$

Similarly, the third consecutive odd integers = $x+4=171+4=175$

8 0

3 years ago

What is bigger 1/5 or .29

n200080 [17]

.29 is bigger.

If you convert 1/5 to a decimal (or simply solve it!) you will end up with .2 or .20
Which is obviously smaller than .29

3 0

3 years ago

Read 2 more answers

PLSSSS HELP IVE TRIED EVERYTHING AHHHHHHH

stepladder [879]

Answer:

<u>Domain</u>: input values (x-values)

<u>Range</u>: output values (y-values)

<u>Increasing function</u>: the average rate of change is positive

<u>Decreasing function</u>: the average rate of change is negative

<u>Constant function</u>: y-values do not vary, regardless of x-values

<h3><u>Graph 1</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-2, 2]

Increasing function: (-2, 0)

Decreasing function: (0, 3)

<h3><u>Graph 2</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-2.5, 2]

Increasing function: (-2, -1) ∪ (1.5, 3)

Decreasing function: (-1, 1.5)

<h3><u>Graph 3</u></h3>

From inspection of the graph, 2 squares = 1 unit.

Domain: [-2, 3]

Range: [-1, 2]

Increasing function: (-2, -1)

Constant: (-1, 1)

Decreasing function: (1, 3)

5 0

2 years ago

PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.

anygoal [31]

Option C: $x=0$ and $x=\frac{5}{2}$ are the solutions.

Explanation:

The equation is $\frac{x}{3} =\frac{x^{2} }{x+5}$

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, $x=0$ and $x=\frac{5}{2}$ are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute $x=0$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}$

Thus, both sides of the equation are equal.

Hence $x=0$ is a true solution.

Now, Let us substitute $x=\frac{5}{2}$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}$

Thus, both sides of the equation are equal.

Hence, $x=\frac{5}{2}$ is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0

3 years ago