Skater A travels with velocity of 3.2 m/s and has a momentum of 200 kg m/s

The _____ deflects these winds to the right in the northern hemisphere and to the Southern Hemisphere

almond37 [142]

Answer:

Coriolis Effect

Explanation:

The Coriolis effect is responsible for the deflection of winds to the right in the Northern hemisphere and to the right in the Southern hemisphere. It is an effect that occurs because of the rotation of the earth around its axis.

The implication of this is that in areas of low pressure in the Northern hemisphere, winds tend to blow in anticlockwise direction, and in areas of high pressure, it blows in a clockwise direction. The opposite of this happens in the Southern hemisphere.

6 0

3 years ago

A 1232 kg car moving north at 25.6 m/s collides with a 2028 kg car moving north at 17.5 m/s . They stick together. In what direc

Citrus2011 [14]

Answer:

I. Angle = 41.7° Northeast.

II. Vr = 7.08m/s

Explanation:

Let the two cars be denoted by A and B

Given the following data;

Mass of car A = 1232 Kg

Velocity of car A = 25.6 m/s

Mass of car B = 2028 Kg

Velocity of car B = 17.5m/s

First of all, we would solve for momentum;

Momentum = mass × velocity

Momentum, M1 = 1232 × 25.6

Momentum, M1 = 31539.2 Kgm/s

Momentum, M2 = 2028 × 17.5

Momentum, M2 = 35490 Kgm/s

Now, let's find the resultant momentum using the Pythagoras theorem;

R² = M1² + M2²

R² = 31539.2² + 35490²

R² = 994721136.6 + 1259540100

R² = 2254261237

Taking the square root of both sides, we have

Resultant momentum, R = 47479.06 Kgm/s

To find the direction;

Angle = tan¯¹(M1/M2)

Angle = tan¯¹(31539.2/35490)

Angle = tan¯¹(0.89)

Angle = 41.7° Northeast.

To find the speed;

R = (M1 + M2)Vr

47479.06 = (31539.2 + 35490)Vr

47479.06 = 67029.2Vr

Vr = 47479.06/67029.2

Vr = 7.08m/s

6 0

3 years ago

If you run a complete loop around an outdoor track of length 400 m in 100 s, find your(a) average velocity and (b) average speed

laila [671]

Answer:

a) 0 m/s

b) 4 m/s

Explanation:

The average velocity would end up being 0 because it is displacement over time and the displacement here is 0. However, speed is total distance over time which here is 400/100 so it is 4.

5 0

3 years ago

A 13 cm long tendon was found to stretch 3.7 mm by a force of 12.1 N . The tendon was approximately round with an average diamet

liq [111]

Answer:

young's modulus $=\frac{stress}{strain}=\frac{0.1990\times 10^{6}}{28.46\times 10^{-3}}=6.99\times 10^6N/m^2$

Explanation:

We have given length of tendon L= 13 cm =0.13 m

Change in length $\Delta L=3.7mm=3.7\times 10^{-3}m$

Force = 12.1 N

Average diameter d =8.8 mm

So $r=\frac{d}{2}=\frac{8.8}{2}=4.4mm=4.4\times 10^{-3}m$

Area $A=\pi\times (4.4\times 10^{-3})^2=60.79\times 10^{-6}m^2$

Now stress $=\frac{force}{area}=\frac{12.1}{60.79\times 10^{-6}}=0.1990\times 10^6N/m^2$

Strain $=\frac{change\ in\ lenght}{length}=\frac{3.7\times 10^{-3}}{0.13}=28.46\times 10^{-3}$

Now young's modulus $=\frac{stress}{strain}=\frac{0.1990\times 10^{6}}{28.46\times 10^{-3}}=6.99\times 10^6N/m^2$

8 0

4 years ago

What is the horizontal acceleration of a ball that is launched horizontally with a velocity of 5.6 m/s?

pochemuha

Once it leaves the bat, the club, or the hand, there is no
horizontal force on it (ignoring air resistance). So it has
no horizontal acceleration (ignoring air resistance).

5 0

3 years ago

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