Skater A travels with velocity of 3.2 m/s and has a momentum of 200 kg m/s
1 answer:
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Answer:
the angular acceleration is 9.7 rad/
Explanation:
given information:
mass of thin rod, m = 3.2 kg
the length of the rod, L = 1.2
angle, θ = 38
to find the acceleration of the rod, we can use the torque's formula as below,
τ = Iα
where
τ = torque
I = inertia
σ = acceleration
moment inertia of this rod, I
I =
τ = F d, d = cosθ
τ = m g cosθ
now we can substitute the both equation,
τ = Iα
α = τ/I
= (m g cosθ)/(
)
= 3gcosθ/2L
= 3 (9.8)cos 38°/(2 x 1.2)
= 9.7 rad/
Answer:
Potential energy
Explanation:
Given data
Weight of the person = 1000 N
Mass of the person =
Speed = 6.26
Kinetic energy is given by
Put the values in above formula we get
When the person reach top point then at this point the velocity is zero & kinetic energy at top point is equals to the potential energy.
Therefore potential energy