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Ksenya-84 [330]
3 years ago
7

A large, 60 turn circular coil of radius 10.0 cm carries a current of 4.2 A. At the center of the large coil is a small 20 turn

coil of radius 0.5 cm carrying a current of 1.0 A. The planes of the two coils are perpendicular. Find the torque exerted by the large coil on the small coil. (Neglect any variation in B due to the large coil over the region occupied by the small coil.)
Physics
1 answer:
Eddi Din [679]3 years ago
4 0

To solve this problem we apply the concepts related to the electric torque generated by the electromagnetic field. Mathematically this Torque can be written under the following relation

\tau = NIAB sin\theta

Here,

N = Number of Turns

I = Current

A = Area

B = Magnetic Field

The maximum torque will be reached when the angle is 90 degrees, then we will have the following relation,

\theta = 90\°C

Magnetic Field is given at function of the number of loops, permeability constant at free space at the perimeter, then

B = \frac{N\mu_0 I}{2\pi r}

B = \frac{(60)(4\pi * 10^{-7})(4.2)}{2\pi (0.1)}

B = 5.04*10^{-4}T

Replacing at the first equation we have,

T = (20)(\pi (0.005)^2)(1)(5.04*10^{-4})

T = 7.91*10^{-7}N\cdot m

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Blue coloured star is hotter than red coloured star.

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3 years ago
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What is the physical significance of momentum. Like velocity gives us how position is changing with respect to time, what does m
disa [49]
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7 0
4 years ago
An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi
alexdok [17]

Actual displacement that he required to move

d_1 = 5.4 km towards North

Displacement that he moved due to snow is

d_2 = 8.1 km at 47 degree North of East

now in vector component form we can say

d_1 = 5.4 \hat j

d_2 = 8.1 cos47 \hat i + 8.1 sin47 \hat j

d_2 = 5.52 \hat i + 5.92 \hat j

now the displacement that is more required to reach the destination is given as

d = d_1 - d_2

d = 5.4\hat j - (5.52 \hat i + 5.92\hat j)

d = -5.52 \hat i - 0.52 \hat j

so the magnitude of the displacement is given as

d = \sqrt{5.52^2 + 0.52^2}

d = 5.54 km

its direction is given as

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4 0
3 years ago
Somebody please help
suter [353]

Answer:

a = 0.1067 [m/s²]

Explanation:

In order to solve this problem, we must first draw a free body diagram with the forces acting on it.

a)

In the attached image we can find the free body diagram.

b)

The net force can be found by performing a sum of forces on the X-axis, these forces are seen in the free body diagram.

∑Fx = Fr

where:

Fr = resultant force [N] (units of Newtons)

F_{r}=275+275-310\\F_{r}=240[N]

c)

Acceleration can be found by means of Newton's second law, which tells us that the sum of the forces in a body or the resulting force is equal to the product of mass by acceleration.

∑F = m*a

where:

m = mass = 2250 [kg]

a = acceleration [m/s²]

240=2250*a\\a=0.1067[m/s^{2} ]

5 0
3 years ago
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