Answer:
a.) 490m
b.) 98m/s
Explanation:
Given that the
Acceleration g = 9.8 m/s^2
Time = 10s
Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,
U = 0
Distance covered = height H
The height can be calculated by using second equation of motion
H = Ut + 1/2gt^2
Substitute g and t into the formula
H = 1/2 × 9.8 × 10^2
H = 490 m
Therefore, she travels as far as 490 m
b.) Her final velocity can be calculated by using third equation of motion
V^2 = U^2 + 2gH
Substitute g and H into the formula.
Remember that U = 0
V^2 = 2 × 9.8 × 490
V^2 = 9604
V = sqrt (9604)
V = 98 m/s
Therefore, her final velocity is 98 m/s
The answer is a, series circuit.
Answer:
R = 3.88 m
Explanation:
As the Chinook salmon leaves the water till it gets back into the water it is performing a projectile motion with the following parameters:
V₀ = Launch Speed = 6.7 m/s
θ = Launch Angle = 29°
R= Range of Projectile= Horizontal Distance Covered by Chinook salmon= ?
The value of the range of a projectile is given by the following formula:
R = (V₀² Sin 2θ)/g
R = [(6.7 m/s)² Sin {(2)(29°)}/(9.8 m/s²)]
R = [(6.7 m/s)² Sin (58°)/(9.8 m/s²)]
<u>R = 3.88 m</u>
Answer:
Therefore, highest point that the cannon ball reaches is 168.7m
Explanation:
the cannon is fired at an angle 30 o to the horizonatal with a speed of 155 m/s
highest point that the cannon ball reaches?
g = 9.8m/s2
Therefore, highest point that the cannon ball reaches is 168.7m
Answer:
The entropy change is 45.2 kJ/K.
Explanation:
mass of water at 100 C = 2 kg
Latent heat of vaporization, L = 2260 kJ/kg
Heat is
H = m L
H = 2 x 2260 = 4520 kJ
Entropy is given by
S = H/T = 4520/100 = 45.2 kJ/K
