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Elodia [21]
3 years ago
10

A park has a 333 meter (\text{m})(m)left parenthesis, start text, m, end text, right parenthesis tall tether ball pole and a 6.8

\,\text{m}6.8m6, point, 8, start text, m, end text tall flagpole. The lengths of their shadows are proportional to their heights.
Mathematics
2 answers:
dybincka [34]3 years ago
6 0

Answer:option B & D are correct

Step-by-step explanation:

Given options are  

                                             A              B          C             D           E        

Tether ball pole shadow      1.35         1.8        3.75        0.6       2

Flagpole shadow                  3.4          4.08      8.35       1.36      4.8

Ratio of corresponding height & shadows  should be same

3 meter tall tether ball pole and a 6.8 tall flagpole

=> Ratio  = 6.8/3    = 68/30  = 34/15  

A    - 3.4/1.35 =   340/135     ≠ 34/15( 306/135)

B  -  4.08/1.8  = 408/180   =  34/15  = 34/15  ( Correct option)

C    8.35/3.75  = 835/375  =  167/75   ≠ 34/15( 170/75)

D  1.36/0.6  = 136/60   =  34/15  = 34/15   ( Correct option)

E  4.8/2  = 48/20   =  12/5   = 36/15    ≠ 34/15

option B & D are correct

lesya [120]3 years ago
6 0

Answer:

B and D

Step-by-step explanation:

Khan says si

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miss Akunina [59]

Answer:

m∠SRT = 33°     ∵ m∠QRT = m∠SRT

Step-by-step explanation:

Given the diagram,

RT bisects ∠SRQ, and m∠QRT = 33°

RT bisecting ∠SRQ means RT will bisect ∠SRQ into two equal angles, which are:

m∠QRT = m∠SRT

as

m∠QRT = 33°

so

m∠SRT = 33°     ∵ m∠QRT = m∠SRT

6 0
3 years ago
H^-16/h^x=1/h^24 can someone help me please
Basile [38]

Given:

Consider the equation is

\dfrac{h^{16}}{h^x}=\dfrac{1}{h^{24}}

To find:

The value of x.

Solution:

We have,

\dfrac{h^{-16}}{h^x}=\dfrac{1}{h^{24}}

Using properties of exponents, we get

h^{-16-x}=h^{-24}       [\because \dfrac{a^m}{a^n}=a^{m-n},a^{-n}=\dfrac{1}{a^n}]

On comparing both sides, we get

-16-x=-24

Add 16 on both sides.

-x=-24+16

-x=-8

Multiply both sides by -1.

x=8

Therefore, the value of x is 8.

5 0
3 years ago
mr richey bought 20 organizer books and 20 staplers for students. each stapler costs 3$. mr richey spent in total of 200$ for th
pantera1 [17]

Answer: $7

Step-by-step explanation: if a stapler cost $3, then 20staplers will cost $60

Amount left will be $200-60=$140

Cost of one organiser will be $140/20

That will be $7

4 0
2 years ago
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Sever21 [200]
I say its 11. Since the distance between the two points is 11. 

6 0
3 years ago
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Check out the photo for the question
Anestetic [448]

Answer:

50

Step-by-step explanation:

42/n³∑k²+12/n²∑k+30/n∑1

=42/n³[n(n+1)(2n+1)/6]+12/n²[n(n+1)/2]+30/n [n]

=7n(n+1)(2n+1)/n³+6n(n+1)/n²+30

=7(n+1)(2n+1)/n²+6(n+1)/n+30

=[7(2n²+3n+1)+6(n²+n)+30n²]/n²

=[14n²+21n+7+6n²+6n+30n²]/n²

=[50n²+27n+7]/n²

=[50+27/n+7/n²]

→50 as n→∞

because 1/n,1/n²→0 as n→∞

4 0
3 years ago
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