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JulijaS [17]
2 years ago
11

What is the sum of the measures of the interior angles of a regular pentagon?​

Mathematics
1 answer:
lana [24]2 years ago
4 0
You slow tjrjfjdjddjdjdjfjdjf
You might be interested in
Write the quadratic equation whose roots are 3 and -1, and whose leading coefficient is 5.
Assoli18 [71]

Answer:

5x² - 10x - 15 = 0

Step-by-step explanation:

Given that the roots are x = 3 and x = - 1, then the factors are

(x - 3) and (x + 1) and the quadratic is the product of the factors, that is

f(x) = a(x - 3)(x + 1) ← a is a multiplier

Here a = 5, thus

f(x) = 5(x - 3)(x + 1) ← expand factors using FOIL

     = 5(x² - 2x - 3) ← distribute parenthesis by 5

     = 5x² - 10x - 15

Thus equation is

5x² - 10x - 15 = 0

6 0
3 years ago
11. Anna's goal is to walk 12 miles a week. This week, she walked 1 and 2/3
elena-s [515]

Answer:

2 Miles

Step-by-step explanation:

1  2/3 x 6 = 10

( She needs to walk 2 more miles )

Tomorrow Anna should run 2 miles to reach her goal.

Please vote for me, i really want to level up, thank you!

7 0
3 years ago
A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2.
Lerok [7]
A) For object with mass m1,
F = m1 * 3
m1 = F/3

For object with mass m2,
F = m2 * 1
m2 = F

Ratio of m1/m2
(F/3) / F = 1/3
6 0
3 years ago
Read 2 more answers
1. What are two numbers that multiply to make -24 and sum to make -5?
charle [14.2K]
1) -8 and 3
because -8+3= -5 and -8x3=24
2) -8 and -5
because -8-5=-13 and -8x-5=40
8 0
3 years ago
Sin(60-theta)sin(60+theta)​
ehidna [41]

Step-by-step explanation:

\sin(60 -  \theta)  \sin(60 +  \theta)  \\  =  \{ \sin(60)  \cos( \theta)  -  \sin( \theta)   \cos(60)  \} \{ \sin(60)  \cos( \theta)  +  \cos(60)  \sin( \theta)  \} \\  =  \{ \frac{ \sqrt{3} }{2}  \cos( \theta)  -  \frac{1}{2}  \sin( \theta)  \} \{ \frac{ \sqrt{3} }{2}  \cos( \theta)  +  \frac{1}{2}  \sin( \theta)  \} \\  \\

from difference of two squares:

{ \boxed{(a - b)(a + b) = ( {a}^{2} -  {b}^{2} ) }}

therefore:

=  \{ {( \frac{ \sqrt{3} }{2}) }^{2}  { \cos }^{2}  \theta \} -  \{ {( \frac{ \sqrt{3} }{2} )}^{2}  { \sin }^{2}  \theta \} \\  \\  =  \frac{3}{4}  { \cos }^{2}  \theta -  \frac{3}{4}  { \sin}^{2}  \theta

factorise out ¾ :

=  \frac{3}{4} ( { \cos }^{2}  \theta  -  { \sin}^{2}   \theta) \\  \\  = { \boxed{ \frac{3}{4}  \cos(2 \theta) }}

3 0
3 years ago
Read 2 more answers
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