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3 years ago

8

Give an equation which describes the intersection of this sphere with the plane z=6.

1 answer:

Setler79 [48]3 years ago

3 0

Answer:

x^2 + y^2 = a

Step-by-step explanation:

a > or = 36

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Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim

geniusboy [140]

Answer:

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

The answer of the above definite integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

Step-by-step explanation:

The given limit interval is

$\lim_{||\Delta|| \to 0} \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i$

$[a, b] = [-8, 6]$

The corresponding definite integral may be written as

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x$

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x$

Bonus:

The definite integral may be solved as

$\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98$

Therefore, the answer to the integral is

$\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98$

5 0

3 years ago

what is the missing side in a right triangle if one leg measures 5 cm and the longest side measures 13 cm

Alika [10]

Answer:

<u>The missing side is 12 cm length</u>

Step-by-step explanation:

1. Let's review the information given to us to solve the case correctly:

Length of the longest side= 13 cm

Length of one leg = 5 cm

2. Using the Pythagorean theorem for finding the length of the second leg, because this is a right triangle:

2nd leg² = Length of the longest side ² - Length of one leg²

2nd leg² = 13 ² - 5 ²

2nd leg² = 169 -25

2nd leg² = 144

2nd leg = √144

2nd leg = 12 cm

<u>The missing side is 12 cm length</u>

3 0

3 years ago

What is the quotient when 1.272 divided by 0.003?

Arte-miy333 [17]

Answer:

The answer is 424.

8 0

2 years ago

Read 2 more answers

If (−4, 11) and (−6, 5) are the endpoints of a diameter of a circle, what is the equation of the circle?

lora16 [44]

Answer:

A. $(x+5)^2+(y-8)^2=100$

Step-by-step explanation:

1. The standard form of the equation of a circle is $(x-h)^{2} + (y-k)^2=r^2$

2. To find the center we require the midpoint of the 2 given points

center = $[\frac{1}{2}(-4-6),\frac{1}{2}(11+5)]$

=(-5,8)

3. The radius is the distance from the centre to either of the 2 given points calculate the radius using the distance formula

d= $\sqrt{(x_{2}+x_{1})^{2} +(y_{2}-y_{1})^{2}$

let $(x_{1},y_{1})= (-5,8) \\$ and $(x_2,y_2)=(-4,11)$

r= $\sqrt{(-4+5)^2+(11-8)^2} =\sqrt{81+9}=10$

--> $(x-(-5)^2+(y-8)^2=10^2$

--> $(x+5)^2+(y-8)^2=100$

4 0

3 years ago

Read 2 more answers

Need help ASAPPPPPPP

patriot [66]

Answer:

8 is the correct answer because coefficient lies before Exponent. Exponent is variable

So 8 is the coefficient.

5 0

2 years ago