Answer:
C. THE CONVERSION OF FRUCTOSE 1,6-BISPHOSPHATE to fructose- 6- phosphate is not catalyzed by phosphofructokinase -1, the enzyme involved in glycolysis.
Explanation:
This statement is true as the enzyme involved in this step is FRUCTOSE-1,6-BISPHOSPHATASE.
Gluconeogenesis is the coversion of non-carbohydrate molecules (lactic acid, amino acids, glycerol) through the pyruvic acid into glucose in the cells.
This process takes place mainly in the liver and occurs during periods of fasting, starvation, low carbohydrate diets.
The pathway of gluconeogenesis involves eleven steps of enzymatic catalyzed reactions.
In the conversion of fructose 1,6- bisphosphate to fructose-6-phosphate is catalyzed by fructose 1,6-bisphosphatase and not by phosphofructokinase -1 which is involved in glycolysis. This step is a rate-limiting step of the pathway.
The conversion of glucose-6-phospahte to glucose is not catalyzes by hexokinase but glucose -6- phosphatase.
I just got this question on my test, the answer is D) glycogen. All excess glucose is stored long-term in the liver and muscle cells as glycogen when animals need it for energy.
Answer:
A 0.015M
Explanation:
Molarity, which refers to the molar concentration of a solution, can be calculated using the formula:
Molarity (M) = mole (n) / volume (L)
Based on the information provided in this question, the solution contains 0.83 g of dissolved KCI.
We can calculate the number of moles of KCl in the solution by using the formula:
Mole = mass ÷ molar mass
Where atomic mass of; K = 39, Cl = 35.5
Molar Mass of KCl = 39 + 35.5
= 74.5g/mol.
Mole = 0.83g/74.5g/mol.
mole = 0.01114
Approximately, n = 0.011mol
Hence, molarity = 0.011mol/0.75L
Molarity = 0.0146
Molarity = 0.015M
Exchanging oxygen and carbondioxide between air and lungs because it just involves breathing system but everything else involves hormones.........
HOPE IT HELPS !!!
The answer is D. The Protista have very little in common with each other besides being unicellular and Eukaryota.
Protista is one of kingdom that consist of any eukaryotic that could not classified as plant, animal or fungi. Since the classification itself based on exclusion, protist group has much less similarity than other group. All protist is unicellular and eukaryote but other than that, they will have many difference in other aspect.
