It is True that Using flowcharts, programmers can break large systems into subsystems that are easier to understand and code.
<h3>What is the use of
flowcharts?</h3>
A flowchart serves a picture consisting the separate steps of a process which is in sequential order and can be used to break large systems into subsystems during programing.
If a more cohesive module is needed, it can be formed into one unit, having the performance of multiple functions.
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Answer:

Step-by-step explanation:


Answer:
slope is 2 and y-intercept is (0, 4)
Step-by-step explanation:
Answer:
80 ft
Step-by-step explanation:
<em>hey there,</em>
<em />
< We know that the rope is 3 pieces long. To make this into an equation, let's just write x + y + z = 150.
Assuming "y" is our second piece, we can tell y = 2x, because it is two times the size of the first piece, which is "x". We also know "z" (our third piece): z = 30.
We can try inputting all the things we know now. x + (2x) + 30 = 150. From here, we can find that x = 40. Since y is our second piece, y = 2x, so 2 x (40) = 80. The second piece would be 80 feet long. >
<u>Hope this helped! Feel free to ask anything else.</u>