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zloy xaker [14]
2 years ago
5

The spring of a dart gun exerts a force on a 0.02 kg dart as it launched from the gun at 20 m/s. What is the dart ke

Mathematics
1 answer:
seraphim [82]2 years ago
7 0

Answer: The dart comes out at 20.00 m/s.

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That looks like a rectangular prism
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Cy+4=d−9y solve for y
tiny-mole [99]

Answer:

Answer:

y= d−4 /c+9

Step-by-step explanation:

cy+4=d−9y

Step 1: Add 9y to both sides.

cy+4+9y=d−9y+9y

cy+9y+4=d

Step 2: Add -4 to both sides.

cy+9y+4+−4=d+−4

cy+9y=d−4

Step 3: Factor out variable y.

y(c+9)=d−4

Step 4: Divide both sides by c+9.

y(c+9)  c+9 = d−4 /c+9

y= d−4 /c+9

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3 years ago
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kirill [66]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Hi, umm pls help<br><br> 1/6(x-5)=1/2(x+6), solve for x <br><br> And can you please explain
Mumz [18]

Answer:

By solving the equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) we found that   x=\frac{23}{2} \text { or }=11 \frac{1}{2}

<u>Explanation:  </u>

Given equation,

\frac{1}{6}(x-5)=\frac{1}{2}(x+6) to find x  

Step: 1 Cross multiply the denominators 2(x-5)=6(x+6)  

Step: 2 Open brackets and simplify the term 2x-10=6x+36  

Step: 3 Bring x terms on one side and simplify the equation the equation obtained is following,  

2x-6x=36+10

 -4x=46  

-x=\frac{46}{4}=\frac{23}{2}=11 \frac{1}{2}

Therefore, we solved x value from the given equation \frac{1}{6}(x-5)=\frac{1}{2}(x+6) as x=\frac{23}{2} \text { or }=11 \frac{1}{2}.

4 0
3 years ago
Martin has a piece of purple yarn that is 3 1/2 inches long he has a piece of yellow yarn that is 3 5/6 inches Long how much lon
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Answer:

2 1/3 longer

Step-by-step explanation:

yw ;)

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2 years ago
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