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algol [13]
3 years ago
6

Y = (x²+3)(2x-6) What is the derivative?

Mathematics
1 answer:
ahrayia [7]3 years ago
4 0

Answer:

y = (x²+3)(2x-6)

  • dy/dx=d(x²+3)(2x-6)/dt=(x²+3)d(2x-6)/dt+(2x-6)d(x²+3)/dt= (x²+3)(2)+(2x-6)(2x)=2x²+6+4x²-12x=6x²-12x+6=6(x²-2x+1)
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The Proof is below.

Step-by-step explanation:

Given:

\overline {LP} \cong \overline{NP}

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Proof:

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\overline {ML} \cong \overline{MN}  ……….{Given}

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Now In ΔLMQ  and ΔNMQ  

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\overline {MQ} \cong \overline{MQ}  ……….{Reflexive Property}

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