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Licemer1 [7]
2 years ago
8

Find the least frequency of incident light that will knock electrons out of the surface of a metal with a work function of 3eV.​

Physics
1 answer:
mixer [17]2 years ago
3 0

Answer:

The frequency must be: 725\,\,10^{12} \,Hz

Explanation:

If the work function of the metal (\phi) is 3 eV, then we can use the formula for the kinetic energy of an ejected electron:

KE= h*f-\phi

considering for the minimum KE = 0, and using the Plank constant h in eV s as: 4.14 * 10 ^(-15) eV s, to solve for the frequency:

h*f=\phi\\4.14*10^{-15} * f = 3\\f=3*10^{15}  /4.14\,\,\frac{1}{s} \\f=725\,10^{12} \,Hz

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Ilia_Sergeevich [38]

Answer:

Potential

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