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Oksana_A [137]
3 years ago
13

Understanding that if we say something unkind to someone else his or her

Physics
1 answer:
OlgaM077 [116]3 years ago
6 0

Answer: Moral

Explanation:

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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

f=12GHz=12\cdot 10^9 Hz is the frequency

c=3.0\cdot 10^8 m/s is the speed of light

So the wavelength of the beam is

\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

y=\frac{m\lambda D}{a}

where

m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

a = 2.0 m is the aperture of the antenna (which corresponds to the width of the slit)

Substituting, we find

y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m

and so, the diameter is

d=2y = 750 m

B) 0.23 W/m^2

First we calculate the area of the surface of the microwave at a distance of 30 km. Since the diameter of the circle is 750 m, the radius is

r=\frac{750 m}{2}=375 m

So the area is

A=\pi r^2 = \pi (375 m)^2=4.42\cdot 10^5 m^2

And since the power is

P=100 kW = 1\cdot 10^5 W

The average intensity is

I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2

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3 years ago
Assume that the blocks are accelerating, and the x components of their accelerations at a certain moment are a1x and a2x. find t
Serga [27]

we know that center of mass is given as

r = (m₁ r_{1x} + m₂ r_{2x})/(m₁ + m₂)

taking derivative both side relative to "t"

dr/dt = (m₁ dr_{1x}/dt + m₂ dr_{2x}/dt)/(m₁ + m₂)

v = (m₁ v_{1x} + m₂ v_{2x})/(m₁ + m₂)

taking derivative again relative to "t" both side

dv/dt = (m₁ dv_{1x}/dt + m₂ dv_{2x}/dt)/(m₁ + m₂)

a= (m₁ a_{1x} + m₂ a_{2x})/(m₁ + m₂)

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3 years ago
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Best exercises for these topics. <br> (have the amount of exercises, have 4 exercises for each.)
Kipish [7]

Answer:

what is the question?

Explanation:

i dont understand

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2 years ago
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During a total lunar eclipse, where is the Moon located?
krok68 [10]

During a total lunar eclipse, the Moon located in the umbra. The answer is letter A. For a total lunar eclipse to occur, the Sun, Earth and Moon must be aligned in a straight line. The Earth’s umbra complete covers the Moon. The earth’s umbra is about 870,000 miles wide.

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37. Which of the following is not used in cal-
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B

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