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muminat
3 years ago
6

A positive charge moves in the direction of an electric field. Which of the following statements are true? Check all that apply.

Check all that apply. The potential energy associated with the charge increases. The amount of work done on the charge cannot be determined without additional information. The electric field does positive work on the charge. The electric field does not do any work on the charge. The potential energy associated with the charge decreases. The electric field does negative work on the charge. SubmitRequest Answer Provide Feedback Next
Physics
2 answers:
Sergio039 [100]3 years ago
5 0

Answer:

The electric field does positive work on the charge.

The potential energy associated with the charge decreases.

Explanation:

We know that force due to electric filed on a charge particle q given as

 F = q E          --------1

If the   positive charge is moving in the direction of electric filed it means that force due to electric field and displacement of particle due to motion is in the same direction.So the work done due to electric filed will be positive.

Work = Force . Displacement

W= F.d

F= W/d            ---------2

From equation 1 and 2

W/d = q E

W/ q = E/ d

We know that voltage difference ΔV

ΔV = E/ d

ΔV =W/ q

So the potential difference will be decrease because charge is positive.So the potential energy will be decreases.

jarptica [38.1K]3 years ago
3 0

Answer:

The potential energy associated with the charge decreases,

The electric field does positive work on the charge.

Explanation:

If a positive charge is moving in the direction of an electric field that it would normally move, the potential energy associated with the charge will decrease because the scenario is similar to what occurs in a constant gravitational field.

Also, when potential energy is lost (decreases), this means positive work is done on the charge.

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7 0
2 years ago
What is the density of iron if 5.0 cm3 has a mass of 39.5g
weqwewe [10]

Answer :\rho = 7.9\ g/cm^3

Explanation :

It is given that

Mass of iron, m = 39.5 g

Volume of iron, V = 5\ cm^3

So, density is :

density, \rho =\dfrac{mass}{volume}

\rho =\dfrac{39.5g}{5cm^3}

\rho = 7.9\ g/cm^3

7 0
3 years ago
You have a 35X objective lens in place, and the numerical aperture of the objective lens is 0.75. The numerical aperture of the
olasank [31]

Answer:

350x

Explanation:

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The magnification of a microscope is given by the product of the magnifications of the eyepiece and and the objective.

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Total magnification

M=m_o\times m_e\\\Rightarrow M=35\times 10\\\Rightarrow M=350

Total magnification is 350x

8 0
3 years ago
On a perfect fall day, you are hovering at low altitude in a hot-air balloon, accelerated neither upward nor downward. The total
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Explanation:

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Hence, the buoyant force equals the weight of air displaced by the balloon, also 20,000 N.

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3 0
3 years ago
A 5cm tall object is placed 4cm in front of a converging lens that has a focal length of 8cm. Where is the image located in ____
OverLord2011 [107]

Answer:

a. -8 cm

Explanation:

d_{o} = distance of the object = 4 cm

d_{i} = distance of the image = ?

f = focal length of the converging lens  = 8 cm

using the lens equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}

d_{i} = - 8 cm

4 0
3 years ago
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