Answer:
21 and 26 totaling 47sticks
Step-by-step explanation:
Th number of sticks form an arithmetic progression
1, 6, 11, 16...
The nth term of an arithmetic progression is expressed as;
Tn = a+(n-1)d
a is the first term = 1
d is the common difference
d = 6-1 = 11-6 = 5
n is the number of terms
The next two terms are the fifth and sixth term
T5 = 1+(5-1)5
T5 = 1+4(5)
T5 = 1+20
T5 = 21
T6 = 1+(6-1)5
T6 = 1+5(5)
T6 = 1+25
T6 = 26
Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks
Answer:
y= -10
Step-by-step explanation:
y=3x-4
y=3*(-2)-4
y= -6-4
y= -10
<span>Simplifying
4x + 5y = 11
Solving
4x + 5y = 11
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-5y' to each side of the equation.
4x + 5y + -5y = 11 + -5y
Combine like terms: 5y + -5y = 0
4x + 0 = 11 + -5y
4x = 11 + -5y
Divide each side by '4'.
x = 2.75 + -1.25y
Simplifying
x = 2.75 + -1.25y</span>
It would be:
(8 x 3 + 6) divided by 15
because of PEMDAS.
Soooooo sorry but I only understood part a and c.
sorry
