Answer:
Yes
Step-by-step explanation:
4 x 3 = 12
5 x 3 = 15
1 litre of 10% solution contains 100mL of iodine
1 litre of 90% solution contains 900mL of iodine
Mixing them will produce 2 litres of solution containing 1000mL of iodine which is 50% iodine.
To produce 8 litres of 50% iodine they can mix 4 litres of 10% and 4 litres of 90%
Answer:
i hope this helps
Step-by-step explanation:
2
-16=0
+16 +16
2
=16
÷2 ÷2
= 8
= 
x= 
-5
+9=0
-9 -9
-5
=-9
÷-5 ÷-5
=1.8
= 
x= 
6
-15=27
+15 +15
6
=42
÷6 ÷6
=7
= 
x=
Sas only because the triangles and usually congruent to me or in my opponion
The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

----------------(from equation 1)
----------------(given p=58 inches)




----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.





as,
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.