The approximate area of each half of △ACB is 28 square feet
<h3>Area of a triangle</h3>
The formula for calculating the area of a triangle is expressed as:
A = 0.5absintheta
Given the following
PB =11ft
<PCB = 65degrees
Using the SOH CAH TOA identity
tan<PCB = 11/CP
CP = 11/tan65
CP = 5.13 ft
Determine the required area
Area = 0.5(11)(5.13)sin90
Area = 5.5 * 5.13
Area . = 28 square ft
Hence the approximate area of each half of △ACB is 28 square feet
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You can find the value of x using the trigonometric function of cosine.
cos x = adj/hyp
cos 49 = x/55
55(cos 49) = x
36.083 = x
Hope I am right :)
7 in, because any value than 7 either makes more than 16 when doubled, or makes it so that the width has to be 0, which would make it a line and not a rectangle.
Answer:
answer is (3,7)
Step-by-step explanation:
Answer:
-6
Step-by-step explanation:
Substitutet -7 for y in -3(9+y): -3(9 - 7) = -3(2) = -6