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Jobisdone [24]
3 years ago
15

Help please someone math

Mathematics
1 answer:
NeX [460]3 years ago
3 0
I think it is c, because the probability is the littlest thing and you add most of it, you are welcome my boy
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Please Help!! Coordinate Plane!!
Black_prince [1.1K]

Answer:

CEDB i think

Step-by-step explanation:

7 0
2 years ago
How can you use properties of multiplication to determine what the factors are
aleksandrvk [35]
Factors can be multiplied together to get the original number.

For example here are the factors of 66.

1 and 66. 2 and 33. 3 and 22. 6 and 11.

1 multiplied by 66 results in the original number 66.

2 multiplied by 33 results in the original number 66.

3 multiplied by 22 results in the original number 66.

<span>6 multiplied by 11 results in the original number 66.</span>
6 0
3 years ago
The histogram displays how many students are in each classroom during homeroom. What percentage of classrooms have 25 students o
Lelechka [254]

Answer:

its 40% but since it's not there it could be 45%

Step-by-step explanation:

hope this helps

3 0
3 years ago
Read 2 more answers
Evaluate. for n = 15 and t = 7
Bingel [31]

Answer:

what is the equation?

Step-by-step explanation:

3 0
3 years ago
From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
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