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sp2606 [1]
2 years ago
12

You want to rent the grill at the park. It cost $20 to

Mathematics
2 answers:
Snowcat [4.5K]2 years ago
5 0
$15 is your answer. Hope this helps!
Hitman42 [59]2 years ago
4 0
I would say 15 or so
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Explain in words how you would evaluate the expression 5.1 + q ÷ 3.4 for q = 28.9
statuscvo [17]
You would plug in twenty eight point nine to the q. So it would be five point one plus twenty eight point nine divided by three point four, which equals thirteen point six.
4 0
2 years ago
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How to find the side length of a square
Tju [1.3M]
Add all sides together to find the length of each side
8 0
3 years ago
What is the area of this figure? Please help.
Ad libitum [116K]

The area of the composite figure can be found by summing the whole area that made up the figure. Therefore, the area of the figure is 213.5m²

<h3>Area of a composite figure</h3>

The area of the composite figure is the sum of the area of the whole figure.

Therefore, the composite figure can be divided into 2 triangles and two rectangles.

Hence,

area of triangle1 = 1 / 2 × 10 × 13 = 65 m²

area of the triangle2 = 1 / 2 × 15 × 7 = 52.5 m²

area of the rectangle1 = 8 × 3 = 24 m²

area of rectangle2 = 7 × 6 = 42 m²

area of rectangle3 = 5 × 6 = 30 m²

Therefore,

area of the composite figure = 65 + 52.5 + 24 + 42 + 30 = 213.5 meters squared

learn more on area here: brainly.com/question/27744042

#SPJ1

8 0
1 year ago
HELP WILL GIVE BRAINLIEST
SVEN [57.7K]

Answer:

5/8 = 20/32

Step-by-step explanation:

if you multiply the denominator and the numerator of 5/8 by 4 it will equal 20/32

4 0
2 years ago
Read 2 more answers
Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (
MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the <em>68–95–99.7 rule for the Normal distribution:</em>  If \large \bar x  is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

\large [\bar x - s, \bar x +s]

around 95% of the data must fall in the interval

\large [\bar x -2s, \bar x +2s] 

around 99.7% of the data must fall in the interval

\large [\bar x -3s, \bar x +3s]

So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>

3 0
2 years ago
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