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3 years ago

What is the value of x in the equation 34x+2=54x−6 ?

Mathematics

1 answer:

elixir [45]3 years ago

4 0

Answer:

The value of x in the equation is: $x=\frac{2}{5}$

Step-by-step explanation:

Given the equation

$34x+2=54x-6$

Subtract 2 from both sides

$34x+2-2=54x-6-2$

$34x=54x-8$

Subtract 54x from both sides

$34x-54x=54x-8-54x$

$-20x=-8$

Divide by both sides by -20

$\frac{-20x}{-20}=\frac{-8}{-20}$

$x=\frac{2}{5}$

Therefore, the value of x in the equation is: $x=\frac{2}{5}$

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Which three lengths could be the lengths

Fed [463]

Given:

The three lengths in the options.

To find:

Which three lengths could be the lengths of the sides of a triangle?

Solution:

If the sum of two smaller sides is greater than the largest side, then the three sides can form a triangle otherwise the triangle is not possible.

In option A, the three sides are 4 cm, 8 cm, 13 cm. Here, the largest side is 13 cm.

Sum of two smaller sides is:

$4+8=12$

$4+8$

So, the triangle is not possible.

In option B, the three sides are 13 cm, 11 cm, 23 cm. Here, the largest side is 23 cm.

Sum of two smaller sides is:

$13+11=24$

$13+11>23$

So, the triangle is possible.

In option C, the three sides are 5 cm, 18 cm, 12 cm. Here, the largest side is 18 cm.

Sum of two smaller sides is:

$5+12=17$

$5+12$

So, the triangle is not possible.

In option D, the three sides are 25 cm, 8 cm, 16 cm. Here, the largest side is 25 cm.

Sum of two smaller sides is:

$8+16=24$

$8+16$

So, the triangle is not possible.

Therefore, the correct option is B. The three lengths 13 cm, 11 cm, 23 cm could be the lengths of the sides of a triangle.

6 0

3 years ago

The radius of the cone is 1.75 inches, and its height is 3.5 inches. If the diameter of the bubble gum ball is 0.5 inches, what

julia-pushkina [17]

Answer:

=11.155 in³

Step-by-step explanation:

Given data:

Radius= 1.75 inches

Height = 3.5 inches

Diameter= 0.5 inches

To find the volume of a cone we will apply the formula:

Volume of a cone = 1/3 πr²h

Substitute the values:

V= 1/3* 3.14 *(1.75)² * 3.5

V=1/3 *3.14*(3.0625)* 3.5

V= 33.66/3

V=11.22 in³

Now find the volume of the bubble gum:

Volume of bubble gum = 4/3 π*r³

Substitute the values:

V= 4/3*3.14*(0.5/2)³

V=4/3*3.14(0.25)³

V=4/3*3.14(0.015625)

V=0.19625/3

V=0.0654 in³

Now subtract the volume of bubble gum ball from the volume of a cone

=11.22 - 0.0654

=11.155 in³

Thus the closest approximation of the volume of the cone that can be filled with flavored ice is 11.155 in³....

6 0

3 years ago

A rectangle has an area of 0.24 of a square. What are some possibility for the length and width of the rectangle? Tell why

VLD [36.1K]

Answer:

<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>

Step-by-step explanation:

Given that the area is 0.24 square meter

The area of a rectangle is given by

$Area=length\times width$ square units

Let x be the length and y be the width.

Since the area is 0.24 square meter, we have the equation:

$Area=x\times y = 0.24$ , with x and y measures in meters

If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.

Now choosing some values for "x", we have:

Put x = 1

$1\times y = 0.24$

∴ y = 0.24

Now put x = 0.5 we get

$0.5\times y = 0.24$

∴ y = 0.48

Put x = 0.25

$0.25\times y = 0.24$

∴ y = 0.96

Put x = 2

$2\times y = 0.24$

∴ y = 0.12

8 0

3 years ago

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-9 equals V over four

gogolik [260]

Answer:

-9=v/4

cross multiply

-9×4=v

-36=v

v=-36

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3 years ago

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Some helppppp!!!!! I’m having trouble

USPshnik [31]

Answer:

1.4*40=56cm, DVD’s he has

1.4*3=4.2cm

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3 years ago

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