Most of the mass of an element is found in the NUCLEUS
Answer:
mark two options:
B. TSN and ISW
D. ISN and TSW
Explanation:
Recall the definition of vertical angles as: <em>those angles opposed by the vertex, and which are the result of two lines that intersect</em>.
In the figure given there are two pairs such angles, one pair I depicted in red, and the other one in blue, while the intersecting lines are shown in green. Notice that when two lines intersect, there are always two pairs of vertical angles being generated.
Therefore, according to the notation given, two boxes need to be checked in the set of options:
1) the one corresponding to : TSN and ISW (blue ones in the attached image)
and
2) the one corresponding to ISN and TSW (red ones in the attached image)
On question 30, that is a displacement- time graph (DT). On this type of graph the gradient is equal to the velocity. B has the steepest gradient, then A and finally C
Now velocity is a vector quantity so it has a direction and speed ( speed doesn't have a fixed direction.)
on the DT graph im going to assume that movement B is a positive velocity with A and C being negative.
So by ranking these: A is the most negative, C is the least negative and B has to be the greatest as it is the only positive velocity.
Q31, The same type of graph is present, by looking at the gradients we can rank the largest and smallest velocities- speeds in the case of the question.
i'll skip my working out as its the same as before:
C, B, A and then D
the same idea as on Q30 applies to Q31 part b,
D,C,B then A
Answer: 3 Amperes
Explanation:
Voltage of battery = 24 volts
R1 = 3Ω
R2 = 5Ω
Total resistance = ?
Current, I = ?
Since the resistors are connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2
Rtotal = 3Ω + 5Ω = 8Ω
Now recall that voltage = current x resistance
i.e V = I x Rtotal
24volts = I x 8Ω
I = 24 volts / 8Ω
I = 3 amperes
Thus, there is 3 Amperes of current in the circuit
-3.33 m/s^2
The soccer player decelerates from 10 m/s
to 0 m/s. Because he decelerates the acceleration will be a negative
value. Since he takes 3 seconds to decelerate, divide his original
velocity by 3
One major point to be careful of is to keep p