The wording of the choices is really unclear. With two resistors in parallel,
here's the situation:
-- The voltage across each resistor is the same as the voltage across
the other one. If the parallel combination is connected to the battery,
then the voltage across each resistor is the full battery voltage.
-- The current through each resistor is (V) / (the resistance of that resistor).
That's the same current as would flow through that resistor if the other one
were not there.
-- As long as the battery or other power supply holds out, neither of these
quantities changes.
Can you match this situation to one of the choices listed ?
It looks to me as if choice 'C' is the one that's most likely
trying to say this.
The ration of the rms speed of 235uf6 to that of 238uf6 is 1.004.
The molecular mass of 235uf6 is 349, while that of 238uf6 is 352.
The rms speed is calculated as
v=√(3RT/m)
Thus the ratio rms speed of 235uf6 to 238uf6 is calculated as
r=√(352/349)=1.004
Answer:
F = mg/2
Explanation:
The full question is attached to the solution of this question.
The forces acting on the box include the weight of the box, the force, F and the tension in the wire attached.
The force required to pull up the box at constant velocity normally is equal to the weight of the box.
W = mg
But in this setup,
The force balance on the box
Sum of upward forces = sum of downward forces.
T + F = mg
But the pulley is frictionless, hence, the force, F is equal to the tension in the wire.
T = F
2F = mg
F = mg/2
Hope this Helps!!!
To answer this problem first is to analyze and understand the problem first and then consider the given and also the gravity that is exert in the ball. Base on my calculation and the use of the formulas the answer are the following:
A. The initial velocity is <span>29.43 m/s
b. The height it reaches is 132.435m</span>
Answer:
c
Explanation:
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