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Pepsi [2]
3 years ago
14

Which pairs of angles in the figure below are verticals angles ? check all that apply.

Physics
1 answer:
Dmitriy789 [7]3 years ago
5 0

Answer:

mark two options:

B. TSN and ISW

D. ISN and TSW

Explanation:

Recall the definition of vertical angles as: <em>those angles opposed by the vertex, and which are the result of two lines that intersect</em>.

In the figure given there are two pairs such angles, one pair I depicted in red, and the other one in blue, while the intersecting lines are shown in green. Notice that when two lines intersect, there are always two pairs of vertical angles being generated.

Therefore, according to the notation given, two boxes need to be checked in the set of options:

1) the one corresponding to : TSN and ISW (blue ones in the attached image)

and

2) the one corresponding to ISN and TSW (red ones in the attached image)

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What happens to its surface temperature as a star changes color from red to blue
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The surface temperature of the star increases when it changes its colour changes from red to blue.
Blue>white>yellow>orange>red
The given series is the temperature decreasing order of stars. Now our sun is considered as a yellow star.
5 0
3 years ago
The magnitude of each force is 208 N the force on the right is applied at an angle 36° and the mass of the block is 17 kg the co
djyliett [7]

Answer:

<em>11.06m/s²</em>

Explanation:

According to Newtons second law of motion

\sm F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - \mu R mgcos \theta = ma_x\\

Given

Mass m = 17kg

Fm = 208N

theta = 36 degrees

g = 9.8m/s²

a is the acceleration

Substitute

208 - 0.148(17)(9.8)cos 36 = 17a

208 - 24.6568cos36 = 17a

208 - 19.9478 = 17a

188.05 = 17a

a = 188.05/17

a = 11.06m/s²

<em>Hence the  the magnitude of the resulting acceleration is 11.06m/s²</em>

6 0
2 years ago
A 10 kg cart is rolling across a parking lot with a velocity of .5 m/s. What is its momentum?
-Dominant- [34]

Hello!

\large\boxed{p = 5  \text{ } kgm/s}

Use the equation for momentum:

p = mv

Plug in the given mass and velocity into the equation:

p = 10 * 0.5

p = 5 kgm/ s

4 0
2 years ago
A 87 arrow is fired from a bow whose string exerts an average force of 105 on the arrow over a distance of 75 .
timofeeve [1]

The solution would be like this for this specific problem:

 

V^2 = 2AS = 2FS/M

V = sqrt(2FS/M) = sqrt(2*105*.75/.087) = 44.52817783 = 42.5 mps

So the speed of the arrow as it leaves the bow is 42.5 mps.

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

6 0
3 years ago
HEre now can somebody help!! <br> Pic is what i need help with
AleksAgata [21]

Answer:

which of the cars are speeding up: c

which of the cars or slowing down: a

which of the cars are maintaning a constant speed: b

Explanation:

8 0
2 years ago
Read 2 more answers
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