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3 years ago

Which factors can affect the amount of friction acting on an object on a solid surface

Physics

2 answers:

seropon [69]3 years ago

3 0

Well gravity is always a factor on the friction of objects.

Alex3 years ago

3 0

If we're talking about friction itself, then mass almost certainly plays a role.

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A student throws a rock horizontally off a 5.0 m tall building. The rock's initial speed is 6.0 m/s. How long will it take the r

Archy [21]

Answer:

The time taken by the rock to reach the ground is 0.569 seconds.

Explanation:

Given that,

A student throws a rock horizontally off a 5.0 m tall building, s = 5 m

The initial speed of the rock, u = 6 m/s

We need to find the time taken by the rock to reach the ground. Using second equation of motion to find it. We get :

$s=ut+\dfrac{1}{2}gt^2\\\\5=6t+\dfrac{1}{2}\times 9.8t^2\\\\t=0.569\ seconds$

So, the time taken by the rock to reach the ground is 0.569 seconds. Hence, this is the required solution.

5 0

3 years ago

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Snow and sleet when they fall to the ground is solar energy or gravitational force?

Nikolay [14]

Gravitational energy

3 0

3 years ago

The force between to objects of charge +Q and -2 Q, respectively, is measured as -2F. If the charge on the first object is doubl

Sloan [31]

The force between to objects of charge +Q and -2 Q, respectively, is measured as -2F. If the charge on the first object is doubled and the distance between the objects is doubled

6 0

4 years ago

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(7) A 2500 lbm car moving at 25 mi/hr is accelerated at a constant rate of 15 ft/s2 up to a speed of 50 mi/hr. What is the force

balandron [24]

Answer:

The force is $F = 1164.6\ lbf$

The time is $\Delta t = 2.44 \ s$

Explanation:

From the question we are told that

The mass of the car is $m = 2500 \ lbm$

The initial velocity of the car is $u = 25 \ mi/hr$

The final velocity of the car is $v = 50 \ mi/hr$

The acceleration is $a = 15 ft/s^2 = \frac{15 * 3600^2}{ 5280} = 36818.2 \ mi/h^2$

Generally the acceleration is mathematically represented as

$a = \frac{v-u}{\Delta t}$

=> $36818.2 = \frac{50 - 25 }{ \Delta t}$

=> $t = 0.000679 \ hr$

converting to seconds

$\Delta t = 0.0000679 * 3600$

=> $\Delta t = 2.44 \ s$

Generally the force is mathematically represented as

$F = m * a$

=> $F = 2500 * 15$

=> $F = 37500 \ \frac{lbm * ft}{s^2}$

Now converting to foot-pound-second we have

$F = \frac{37500}{32.2}$

=> $F = 1164.6\ lbf$

7 0

3 years ago

Which statements are true about the flow of blood in the body? Check all that apply.

Trava [24]

Answer:

i need some explanation

Explanation:

4 0

4 years ago