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2 years ago

Look at the picture.

Mathematics

2 answers:

Slav-nsk [51]2 years ago

7 0

A is the correct answer

alexira [117]2 years ago

6 0

A is the correct answer

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X=1/16y^2 the directrix of the parabola is

yan [13]

To solve this problem you must apply the proccedure shown below:

1. You have the following equation of a parabola, given in the problem above:

x=1/16y^2

2. Then, based on the graph attached, you have:

p=y^2/4x
p=8^2/(4)(4)
p=64/16
p=4

3. The directrix is:

directrix=h-p
directrix=0-4
directrix=-4

The answer is:-4

3 0

2 years ago

What is the value of x (7x+34) if there is any work included i need that too plsss and thanks

katen-ka-za [31]

Answer:

x(7x+34)

=(x)(7x+34)

=(x)(7x)+(x)(34)

=7x2+34x

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

From a box containing 10 cards numbered 1 to 10, four cards are drawn together. The probability that their sum is even is 21 21

ankoles [38]

Answer:

Step-by-step explanation:

We know that between 1 to 10 there are 5 even and 5 odd numbers.

We could get 4 even cards , 4 odd cards or 2 odd and 2 even cards

Let´s check all this combinations

Case 1: When all 4 numbers are even:

We are going to take 4 of the 5 even numbers in the box so we have

$5C4=5$

Case 2: When all 4 numbers are odd:

We are going to take 4 of the 5 odd numbers in the box, so we have

$5C4=5$

Case 3: When 2 are even and 2 are odd:

We are giong to take 2 from 5 even and odd cards in the box so we have

$5C2 * 5C2$

Remember that we obtain the probability from

$\frac{Number-of-favourable-Outcome}{Total-number-of-outcomes}$

So we have the number of favourable outcomes but we need the Total cases for drawing four cards, so we have that:

We are taking 4 of the 10 cards:

$10C_4=210$

Hence we have that the probability that their sum is even

$\frac{5+5+100}{210}=\frac{11}{21}$

8 0

2 years ago

What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i

Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

Step-by-step explanation:

The question is incomplete:

What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions?

We can model this as a binomial random variable, with p=0.57 and n=14.

$P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}$

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

$P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\$

$P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\$

$P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\$

$P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886$

7 0

3 years ago

Pls help which one is it

ValentinkaMS [17]

Answer:

Step-by-step explanation:

4 0

3 years ago