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geniusboy [140]
3 years ago
12

Need someones help on this!

Mathematics
2 answers:
mixer [17]3 years ago
6 0

Answer:

The answer is the third one or (9^(4) (9)  

Step-by-step explanation:

Paha777 [63]3 years ago
4 0

Answer:

1st, 3rd, and 4th box.

Step-by-step explanation:

9^5=59049

9^2=81   9^3=729    729*81=59049              yes

9^5=59049   59049x9=531441                     no

9^4=6561    6561*9=59049                           yes

9^2=81      81x81=6561     6561*9=59049     yes

9^3=729   729x729=531441                          no

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To find the slope, use the equation slope=rise/run.
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True or False? The Blue Radius is Perpendicular to the Green Chord.
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As, both the arms are equal, they must be perpendicular to each other.

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3 years ago
Read 2 more answers
23% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and as
zlopas [31]

Answer:

a) There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

b) There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

c) There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

Step-by-step explanation:

There are only two possible outcomes. Either the student use credit cards because of the rewards program, or they use for other reason. So, we can solve this exercise using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

10 students are randomly selected, so n = 10.

23% of college students say they use credit cards because of the rewards program. This means that \pi = 0.23

(a) exactly two

This is P(X = 2).

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

There is a 29.42% probability that the number of college students who say they use credit cards because of the rewards program is exactly two.

(b) more than​ two

This is P(X > 2).

Either a value is larger than two, or it is smaller of equal. The sum of the decimal probabilities of these events must be 1. So:

P(X \leq 2) + P(X > 2) = 1

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

So

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 0) = C_{10,0}.(0.23)^{0}.(0.77)^{10} = 0.0733

P(X = 1) = C_{10,1}.(0.23)^{1}.(0.77)^{9} = 0.2188

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0733 + 0.2188 + 0.2942 = 0.5863

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.5863 = 0.4137

There is a 41.37% probability that the number of college students who say they use credit cards because of the rewards program is more than two.

(c) between two and five inclusive.

This is

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{10,2}.(0.23)^{2}.(0.77)^{8} = 0.2942

P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343

P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225

P(X = 5) = C_{10,3}.(0.23)^{5}.(0.77)^{5} = 0.0439

So

P = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.2942 + 0.2343 + 0.1225 + 0.0439 = 0.6949

There is a 69.49% probability that the number of college students who say they use credit cards because of the rewards program is between two and five, inclusive.

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Answer:

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Step-by-step explanation:

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Please I need help with this
Firdavs [7]

Answer:

I can help, but what is the equation?

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3 years ago
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