All categories

2 years ago

Need someones help on this!

Mathematics

2 answers:

mixer [17]2 years ago

6 0

Answer:

The answer is the third one or (9^(4) (9)

Step-by-step explanation:

Paha777 [63]2 years ago

4 0

Answer:

1st, 3rd, and 4th box.

Step-by-step explanation:

9^5=59049

9^2=81 9^3=729 729*81=59049 yes

9^5=59049 59049x9=531441 no

9^4=6561 6561*9=59049 yes

9^2=81 81x81=6561 6561*9=59049 yes

9^3=729 729x729=531441 no

You might be interested in

What is the sum of all exterior angles of a regular octagon

8090 [49]

The 8 exterior angles of a regular octagon add up to 360 degrees

3 0

2 years ago

What is the slope of the line?

Dmitry_Shevchenko [17]

Answer:

the slope is 3/2

3 0

3 years ago

The brackets for a shelf are in the shape of a triangle. Find the angles of the triangle if the

zimovet [89]

Answer:

Step-by-step explanation:

2x+3x+5x = 180°

x = 18°

Angles: 36°, 54°, 90°

6 0

3 years ago

The table shows how many of each type of movie are being shown at a theater.

alexira [117]

Answer:

ratio is 5isto 4 byan action and drama

7 0

2 years ago

Evaluate the integral. (sec2(t) i t(t2 1)8 j t7 ln(t) k) dt

polet [3.4K]

If you're just integrating a vector-valued function, you just integrate each component:

$\displaystyle\int(\sec^2t\,\hat\imath+t(t^2-1)^8\,\hat\jmath+t^7\ln t\,\hat k)\,\mathrm dt$

$=\displaystyle\left(\int\sec^2t\,\mathrm dt\right)\hat\imath+\left(\int t(t^2-1)^8\,\mathrm dt\right)\hat\jmath+\left(\int t^7\ln t\,\mathrm dt\right)\hat k$

The first integral is trivial since $(\tan t)'=\sec^2t$ .

The second can be done by substituting $u=t^2-1$ :

$u=t^2-1\implies\mathrm du=2t\,\mathrm dt\implies\displaystyle\frac12\int u^8\,\mathrm du=\frac1{18}(t^2-1)^9+C$

The third can be found by integrating by parts:

$u=\ln t\implies\mathrm du=\dfrac{\mathrm dt}t$

$\mathrm dv=t^7\,\mathrm dt\implies v=\dfrac18t^8$

$\displaystyle\int t^7\ln t\,\mathrm dt=\frac18t^8\ln t-\frac18\int t^7\,\mathrm dt=\frac18t^8\ln t-\frac1{64}t^8+C$

8 0

3 years ago