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kenny6666 [7]
4 years ago
11

Below is the graph of f ′(x), the derivative of f(x), and has x-intercepts at x = –3, x = 1 and x = 2. There are horizontal tang

ents at x = –1.5 and x = 1.5. Which of the following statements is true?
A) f has a relative minimum at x = 1.5
B) f has relative maximum at x = -1.5
C) f is decreasing on the interval from x = 1 to x = 2
D) none of these are true
https://seminole.flvs.net/webdav/assessment_images/educator_apcalcab_v14/08_01_04.gif
Mathematics
1 answer:
guapka [62]4 years ago
5 0

the derivitive is just the slope

minimum happens when the derivitive goes from negative to positive, imagine a slope of the function, the minimum is where the slope goes from neative to positive, and to get there, it has to pass through 0

max happens when the derivitive goes from positive to negative

increaseing is when the derivitive is positive



so, based on what you said, the slope of f(x) is 0 at x=-3, x=1 and x=2 since those are where the derivitive is 0 (derivitive is just the slope)

A and B are wrong because the derivitive isn't 0 at those points

C is correct because increasing means that the derivitive is positive, and so therefo since the only hoirontal place in between 1 and 2 is 1.5, it must remain positive throughout and not dip down, C is right

D is wrong then




answer is C
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Step-by-step explanation:

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Find the coordinates of the midpoint of XL if X is at (-3, 4) and and L is at (7, 12)
abruzzese [7]

Answer:

The answer is

<h2>( 2 , 8 )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = ( \frac{x1 + x2}{2}  , \:  \frac{y1 + y2}{2} )

where

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From the question the points are

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The midpoint is

M = ( \frac{ - 3 + 7}{2}  , \:  \frac{4 + 12}{2} ) \\  = ( \frac{4}{2} , \:  \frac{16}{2} )

We have the final answer as

<h3>( 2 , 8 )</h3>

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