Answer:
a) 7 were 30 or younger
4 of ≤ 30 and 3 of ≥ 30 has no facial hair
b) as attached
c) c) 5/15= 1/3 ( 33.33%) of men older than 30 has facial hair, in total group
0r 5/8 = 0.625 (62.5%) of men older than 30 in his age group has facial hair
Step-by-step explanation:
a) b) shown in attached
c) 5/15= 1/3 ( 33.33%) of men older than 30 has facial hair, in total group
0r 5/8 = 0.625 (62.5%) of men older than 30 in his age group has facial hair
Given:
The equation is:
To find:
The value of y.
Solution:
We have,
On simplification, we get
Since LHS=RHS and the equation is free from the variable y, therefore the given equation is true for all real values of y.
Hence, all real values of y are solutions.
Explanation:
<h3>S + T = R</h3>Suppose we define ...
a(x) = 2x, for 0 ≤ x ≤ 1
b(x) = x^2, for 0 ≤ x ≤ 1
Then we have the following:
c(x) = a(x) +b(x) = 2x +x^2, for 0 ≤ x ≤ 1
S = max(a(x)) = a(1) = 2
T = max(b(x)) = b(1) = 1
R = max(c(x)) = c(1) = 2 +1 = 3
This value of R satisfies S + T = R.
We note that for x=p=1, we have S = a(p), T = b(p), and R = c(p). The first attachment illustrates this case.
__
<h3>S + T ≠ R</h3>Suppose we define ...
a(x) = x, for 0 ≤ x ≤ 1
b(x) = 1 -x^2, for 0 ≤ x ≤ 1
c(x) = a(x) +b(x) = x + 1 -x^2, for 0 ≤ x ≤ 1
Then we have the following:
S = max(a(x)) = a(1) = 1
T = max(b(x)) = b(0) = 1
R = max(c(x)) = c(0.5) = 1.25 ≠ 1 + 1 = 2
This value of R does not satisfy S + T = R.
We note that for p, q, r we have S = a(p), T = b(q), R = c(r) and p≠q≠r. The second attachment illustrates this case.
Answer: 0.9726
Step-by-step explanation:
Let x be the random variable that represents the distance the tires can run until they wear out.
Given : The top-selling Red and Voss tire is rated 50,000 miles, which means nothing. In fact, the distance the tires can run until they wear out is a normally distributed random variable with a 67,000 miles and a
5,200 miles.
Then , the probability that a tire wears out before 60,000 miles :
[using p-value table for z]
Hence, the probability that a tire wears out before 60,000 miles= 0.9726