Make an equation system based on the problem
<span>Jason and Mara have $74
</span>⇒ j + m = 74
<span> Jason has $6 more than 1/3 as much money as Mara has
</span>⇒ j = (1/3)m + 6
<span>
Then, solve the equation by subtitution
j + m = 74
(1/3)m + 6 + m = 74
(1/3)m + m = 74 - 6
(1/3)m + (3/3)m = 68
(4/3)m = 68
m = 68 </span>÷ 4/3
m = 68 × 3/4
m = 51
Mara has $51
j + m = 74
j + 51 = 74
j = 74 - 51
j = 23
Jason has $23
:If PQRS is a parallelogram with two adjacent congruent sides, then the quadrilateral yielded becomes a rhombus:
A rhombus is a quadrilateral that has the same properties as a parallelogram but all sides are congruent
I hope this helps you
49 <61 <64
7^2 <61 <8^2
7<square root of 61 <8
Answer:
No solutions
Step-by-step explanation:
4(2x-3)=2(4x-6)
Same components are present on both sides of equal sign, therefore NO SOLUTIONS are possible.
The base should be 4.
Area=1/2* b *h
4*7=28/2=14.
