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Rzqust [24]
3 years ago
9

there are 3 red marbles,4 blue marbles,2 green marbles, 6 clear marbles in a burlap bag. One marble is randomly pulled from the

bag. What is the probability the marble was green?
Mathematics
1 answer:
creativ13 [48]3 years ago
4 0
2/15 so 13.3% ?

I’m not entirely sure if this is right but I think it’s getting there...
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Exponential growth and decay:
Stella [2.4K]

Answer:

125 g

Step-by-step explanation:

500/2=250

250/2=125

7 0
3 years ago
Read 2 more answers
Please help due today
alisha [4.7K]
77.) x= {-5, 6}
78.) x= {-4, 9}
79.) x= {5/3, 2}
80.) x= {1/9, 3}
81.) x= {-6, 18}
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6 0
2 years ago
Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap
bazaltina [42]

Answer:

Part 1) A=36(\pi-2)\ cm^2

Part 2) P=6(\pi+2\sqrt{2})\ cm

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)

we have that the base and the height of triangle is equal to the radius of the circle

r=12\ cm\\b=12\ cm\\h=12\ cm

substitute

A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)

A=(36\pi-72)\ cm^2

simplify

Factor 36

A=36(\pi-2)\ cm^2

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r

substitute the given values

C=\frac{1}{2}\pi (12)

C=6\pi\ cm

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

AC=\sqrt{12^2+12^2}

AC=\sqrt{288}\ cm

simplify

AC=12\sqrt{2}\ cm

Find the perimeter

P=(6\pi+12\sqrt{2})\ cm

simplify

Factor 6

P=6(\pi+2\sqrt{2})\ cm

6 0
3 years ago
1/4 of what gets me to 45
gregori [183]

1/4 of 180 gets you the answer 45

4 0
3 years ago
List of reading his cell phone and monthly service please try and sell offers a new phone for $50 in unlimited service for a mon
Shtirlitz [24]

Answer:

After 5 months the cost of the two phones and monthly service be the same.

Step-by-step explanation:

1st service cost = $50 + $40x, where "x" represents the number of months

2nd service cost = $50x

Now we have to find the number of months the cost of the two phones and monthly service be the same.

Now we have to equivate and find the value of x.

50x = 50 + 40x

Subtracting 40x from both sides, we get

50x - 40x = 50 + 40x - 40x

10x = 50

Dividing both sides by 10, we get

x = 50/10

x = 5

After 5 months the cost of the two phones and monthly service be the same.

Hope you will understand the concept.

Thank you.


3 0
3 years ago
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