Okay, first we need to figure out what one would make. We need to figure out the area of the base x height. The diameter is 8 so we will cut that to 4 so we can do piR2! 3.14x16 would be 50.24. Then we mutiply that by 10 to get 502.4cm3! Okay, now we would divide 2000/502.4 to find out how many times we would have to make the containers to get to 2000. The answer is 3.98, which we will have to round up since its asks for the minimum and you cant make a container 3.98 times. So the answer is 4!
x = 6
given f(x) = 310, we obtain the equation
10 + 50x = 310 ( subtract 10 from both sides )
50x = 300 ( divide both sides by 50 )
x = = 6
-5v = 6v + 5 - v
-5v - 6v + v = 5
-11v + v = 5
-10v = 5
v = 5/-10
v = -1/2
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-3(b+9)=-6
-3b-27=-6
-3b=-6+27
-3b= 21
b= 21/-3
b=7
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-22=-p-12
-22+12=-p
-10=-p
10=p
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-2/5=-1/3m+3/5
-2/5-3/5=-1/3m
-1=-1/3m
-3=m
Answer:
Step-by-step explanation:
141
The 4 is in the tenth place...so you have to look at the number beside it to see if you round up or down. It's a 6, which is greater than 5 so you round up.
3.5