dont know the answer at all
Step-by-step explanation:
<h3>
Hello there today we will solve your problem</h3>
here is our equation,
,
Now we will plug in our numbers
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simplify it and we get
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Step-by-step explanation:
Geometric Sequence formula for general term:
an = a1(r^n-1)
a1 = 4 × (-5)^1-1
a1 = 4
r = -5
Summation formula for geometric sequence :
Sn = a1 ( 1 - r^n / 1 - r )
...<em>take n from the top of the summation.</em>
= 4 ( 1 -(-5)^6 / 1 -(-5)
= -10416.
-0.75 is a rational number because it can be expressed as the fraction -3/4 and it is an integer
