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Natalka [10]
3 years ago
6

Find the two numbers whose sum is 29 and whose difference is 15.

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

a = 22

b = 7

Step-by-step explanation:

Let the two numbers be represented as a and b.

a + b = 29

a - b = 15

Using elimination method

Add both equations

2a = 44

Divide both sides by 2 to get a

2a/2 = 44/2

a = 22

Now substitute a = 22 in any of the equations to get b .

Using the first equation, we have

a + b = 29

22 + b = 29

Subtract 22 from both sides of the equation

22 - 22 + b = 29 - 22

b = 7

Therefore the two numbers are 22 and 7

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Irina-Kira [14]

Answer:

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Step-by-step explanation:

−2x−40=8(1−x)

Step 1: Simplify both sides of the equation.

−2x−40=8(1−x)

−2x+−40=(8)(1)+(8)(−x)(Distribute)

−2x+−40=8+−8x

−2x−40=−8x+8

Step 2: Add 8x to both sides.

−2x−40+8x=−8x+8+8x

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Step 3: Add 40 to both sides.

6x−40+40=8+40

6x=48

Step 4: Divide both sides by 6.

\frac{6x}{6} =\frac{48}{6}

to get the answer

x=8

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3 years ago
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