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shtirl [24]
3 years ago
15

Test III: Translate the following equations into verbal phrase.

Mathematics
1 answer:
puteri [66]3 years ago
7 0

Answer:

waiting for the bus

Step-by-step explanation:

I'm going back home wait for my answer

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(p-4)^2=4p complete the square if possible
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Answer:

p=6+2 \sqrt{5}, p=6-2 \sqrt{5}

Step-by-step explanation:

Step 1: Given expression is (p-4)^{2}=4 p.

Step 2: To write the equation in the quadratic form, subtract 4p from both sides of the equation.

\Rightarrow(p-4)^{2}-4 p=4 p-4 p

\Rightarrow p^{2}-8 p+16-4 p=0

\Rightarrow p^{2}-12 p+16=0

\Rightarrow p^{2}-12 p=-16

Step 3 :Add\left(\frac{-12}{2}\right)^{2} on both sides of the equation.

\Rightarrow p^{2}-12 p+\left(\frac{-12}{2}\right)^{2}=-16+\left(\frac{-12}{2}\right)^{2}

\Rightarrow p^{2}-12 p+36=-16+36

\Rightarrow(p-6)^{2}=20

Step 4: Taking square root on both sides of the equation.

(p-6)=\pm \sqrt{20}

p=6 \pm 2 \sqrt{5}

Hence, p=6+2 \sqrt{5}, p=6-2 \sqrt{5}.

3 0
4 years ago
Find the value of y^2 when y= -2
Neko [114]

Answer:

4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

y²

y = -2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>y</em>:                    (-2)²
  2. Exponents:                          4
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