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timofeeve [1]
3 years ago
5

Please Help ASAP!! Will Mark BRAINLIEST! Solving Equations with Distributive Property.

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0

Step-by-step explanation:

Explanation in the pic

abcdefg

antiseptic1488 [7]3 years ago
6 0

Answer:

1: k = 7

2: x= - 3

Step-by-step explanation:

sorry i don't know if u need an explanation

hope it helped tho

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Find the value of tangent for angle A
gavmur [86]
AC = √(40²-12²) = √(1600-144) = √1456 = 4√91

tanA = 12/4√91 = 3/√91 = 3√91/91


option а.
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Explain what the mean absolute deviation is in general. Explain what the MAD means in the context of Robin and Evelyn’s data.
sergij07 [2.7K]

Answer: The MAD describes the average distance from a data point to the mean. It measures variability. For this data, it shows that Evelyn’s scores varied slightly more than Robin’s.

Step-by-step explanation: Add 8+1+5+0+12 and divide it by 5 and get 5.2

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2 years ago
Simplify each expression. Assume that all variables are positive.
kozerog [31]
Q1. The answer is  \frac{8x^{3}y^{6}  }{27}

( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} } \\  \\ 
  \frac{ x^{a} }{ x^{b} }= x^{a-b}  \\  \\ 
( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\  \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=
\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\  \\ 
 (x^{a} )^{b} = x^{a*b}  \\  \\ 
\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } =  \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} = 
= \frac{8x^{3}y^{6}  }{27}

Q2. The answer is 1/16

(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} =  \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\  \\  (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } }  \\  \\ 

\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } =  \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}


Q3. The answer is a^{ \frac{7}{6} }

a^{ \frac{2}{3} } * a^{ \frac{1}{2} }  \\  \\ 
 x^{a}* x^{b}  =x^{a+b}  \\  \\ 
a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }
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experimental study.

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This study is an example of an experimental study.

The type of training program is the independent variable. The number of incidents of bullying is the dependent variable.

Since the participants of our study are affected directly in the research (the fourth-grade children) by not training against anti-bullying, the study is experimental research.

An independent variable is one that is somehow controlled or adjusted to evaluate the effects of a different variable, the dependent. Since we control whether we do bullying training here or not, our kind of training program is our independent variable, which is our dependent variable since we measure its impact on instances of bullying no.

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3 years ago
Is 15/12 greater than 5/6
3241004551 [841]

Answer:

no

Step-by-step explanation:

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