Question

Which equation has the same soultions as X^2+6x-7=0

Answer 1

$x^{2} +6x-7=0$
Solve by formula : $x_{1.2} = \frac{-b+ \sqrt{ x^{2-4ac} } }{2a}$
$a=1,b=6,c=-7$

$x_{1.2} = \frac{(-6)+ \sqrt{ 6^{2}-4(-7) } }{2}$

$x_{1.2}= \frac{\sqrt{(-6)+ \sqrt{ 6^{2}+28 } } }{2}$

$x_{1.2} = \frac{(-6)+ \sqrt{36+28 } }{2}$

$x_{1.2} = \frac{(-6)+ \sqrt{64} }{2}$

$x_{1.2} = \frac{(-6)+8}{2}$

First solution:
$x_{1} = \frac{(-6)+8}{2}$

$x_{1}= \frac{\not 2}{\not 2}$

$x_{1} =1$
Second solution:
$x_{2} = \frac{-6-8}{2}$

$x_{2} =-14:2$

$x_{2} =-7$

The answer is: $x_{1} =1$ , $x_{2} =-7$

Answer 2

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